why is it easier to read black text on a white background than to read green text or text of any light color?

1 answer:

4 0

Because the light colors will only work on a dark background, as dark colors will only work on a light background. If light color were on the white background not only will it be nearly impossible to read, the letters with have to be much larger for older people to read or see. Therefore, Black letters on a white background is most common. But a Black background with white letters could also work, kind of like a chalkboard.

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What distinguishes mass from weight?

Hunter-Best [27]

Answer:

The answer is A.) Mass is a measure of the amount of matter in an object, while weight is a measure of the force of gravity on the object.

Explanation:

Your weight would change if you went to the moon because the gravitational pull is different but your mass would stay the same because the amount of matter in you wouldnt change.

4 0

3 years ago

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Circumference of a circle given the radius or diameter? explain why or why not

djyliett [7]

Circumference of a circle can be calculated if the radius or the diameter is given.

<u>Explanation</u>:

Circumference or the perimeter of a circle can be calculated if the radius or the diameter of the circle is given.
This is calculated by the formula - 2 * pi * r (if radius is given) and pi * d (if diameter is given) where pi = 3.14, r = radius and d = diameter
This calculation is based on the fact that the circumference is three and a little more times that of the radius. Since the diameter is double that of the radius, when the diameter is given formula becomes pi*d.

3 0

3 years ago

During an ultrasound, sound waves are sent by a transducer through muscle tissue at a speed of 1300 m/s. Some of the sound waves

alina1380 [7]

$2.3 \times 10^{-5} \text { seconds }$ is the time taken by the transducer to detect the reflected waves from the metal fragment after they were first emitted

Option C

<u>Explanation:</u>

Given data:

speed, v = 1300 m/s

distance, d = 3.0 cm = $3.00 \times 10^{-2} \mathrm{m}$

We need to calculate the time taken by the transducer to detect the reflected waves from the metal fragment after they were first emitted.

As we know, the velocity is the ratio of distance and the time travelled by an object. The equation form is given by,

$\text {velocity, } v=\frac{\text {distance }(d)}{\text {time}(t)}$

By applying the given values to the above equation, we get

$1300=\frac{3.00 \times 10^{-2}}{t}$

$t=\frac{3.00 \times 10^{-2}}{1300}=0.002307 \times 10^{-2}=2.3 \times 10^{-5} \text { seconds }$

7 0

4 years ago

When the valve between the 2.00-L bulb, in which the gas pressure is 2.00 atm, and the 3.00-L bulb, in which the gas pressure is

padilas [110]

Answer:

$P_{C} = 3.2\, atm$

Explanation:

Let assume that gases inside bulbs behave as an ideal gas and have the same temperature. Then, conditions of gases before and after valve opened are now modelled:

Bulb A (2 L, 2 atm) - Before opening:

$P_{A} \cdot V_{A} = n_{A} \cdot R_{u} \cdot T$