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8_murik_8 [283]
3 years ago
15

Why a common measuring system is important

Chemistry
1 answer:
Gekata [30.6K]3 years ago
6 0
So scientist around the world can share there info without having to convert and doing extra work.
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What happens to the conductivity of water when an acid is dissolved in it for bases?
Degger [83]
An Arrhenius acid is therefore any substance that ionizes when it dissolves<span> in </span>water to give the H+<span>, or hydrogen, ion. An Arrhenius </span>base<span> is any substance that gives the OH</span>-<span>, or hydroxide, ion when it </span>dissolves<span> in </span>water<span>.</span>
8 0
2 years ago
A strand of hair is approximately 50 μm thick. If the diameter of an atom is 1 × 10-10 m, how many atoms thick is a strand of ha
Kazeer [188]

Thickness of strand hair = 50 μm

Diameter of an atom  = 1 \times 10^{-10} m

Now, with the help of conversion factors, convert thickness in micrometer into meter i.e. 1 micrometer = 10^{-6}m

So, thickness of strand hair =50 μm= 50 \times 10^{-6} m

Therefore,

number of atoms thick is a strand of hair =  50 \times 10^{-6}m\times \frac{1 atom}{1 \times 10^{-10}m}

= 50\times 10^{4}atoms

Hence, number of atoms is 50\times 10^{4}atomsthick is a strand of hair.


6 0
3 years ago
Read 2 more answers
An ionic compound is
Musya8 [376]

Answer:

a compound

welcome

7 0
3 years ago
Read 2 more answers
Which kingdom(s) include organisms that are autotrophic and heterotrophic?
Gnom [1K]

Answer:

Explanation:

Plantae Animalia Archaebacteria and Animalia Protista and Eubacteria . Protista and Eubacteria kingdom(s) include organisms that are autotrophic or heterotrophic

6 0
3 years ago
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A 25.00-mL aliquot of a nitric acid solution of unknown concentration is pipetted into a 125-mL Erlenmeyer flask and 2 drops of
Semenov [28]

Answer:

0.0611M of HNO3

Explanation:

<em>The concentration of the NaOH solution must be 0.1198M</em>

<em />

The reaction of NaOH with HNO3 is:

NaOH + HNO3 → NaNO3 + H2O

<em>1 mole of NaOH reacts per mole of HNO3.</em>

That means the moles of NaOH used in the titration are equal to moles of HNO3.

<em>Moles HNO3:</em>

12.75mL = 0.01275L * (0.1198mol / L) = 0.0015274 moles NaOH = Moles HNO3.

In 25.00mL = 0.025L -The volume of the aliquot-:

0.00153 moles HNO3 / 0.025L =

<h3> 0.0611M of HNO3</h3>
7 0
3 years ago
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