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2 years ago

An object's starting position is at point A and its final position is at point B.

Physics

1 answer:

salantis [7]2 years ago

4 0

B- we would need the time to fulfill the formula distance = speed x time

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A(n) 0.2 kg object is swung in a vertical circular path on a string 0.1 m long. The acceleration of gravity is 9.8 m/s2 . If a c

Leya [2.2K]

Answer:

$T=83.37N$

Explanation:

Since the object is under a circular motion, according to Newton's second law, when the object is at the top of the circle we have:

$\sum F_y: T-mg=F_c$

Where $F_c$ is the centripetal force and is given by:

$F_c=ma_c=m\frac{v^2}{r}$

Replacing and solving for T:

$T=m\frac{v^2}{r}+mg\\T=0.2kg\frac{(6.38\frac{m}{s})^2}{0.1m}+0.2kg(9.8\frac{m}{s^2})\\T=83.37N$

8 0

3 years ago

A mass hanging from a spring oscillates with a period of 0.35 s. Suppose the mass and spring are swung in a horizontal circle, w

Annette [7]

Answer:

66 rpm

Explanation:

The period of oscillation is given by

$T=2\pi \sqrt{\frac {m}{k}}$

$\frac {k}{m}=\frac {4\pi^{2}}{T^{2}}$ where T is time period of oscillation which is given as 0.35 s, k s spring constant and m is the mass of the object attached to the spring.

Also, net force is given by

Net force= $m\omega^{2} L$

$\omega=\sqrt{\frac {k\triangle L}{mL}}$ where $\triangle L$ is the elongation, L is original length, $\omega$ is the angular velocity

Substituting the equation of $\frac {k}{m}$ into the above we obtain

$\omega=\sqrt {\frac {4\pi^{2}\triangle L}{T^{2} L}}$

$\omega=\sqrt {4\pi^{2}\times 0.15L}{0.35^{2}\times L}}=6.952763\approx 6.95 rad/s$

$6.95\times\frac {60 s}{2\pi rad}\approx 66 rpm$

6 0

3 years ago

Freezing involves the ______________ of latent heat and a change is state from the ______________ phase to the solid phase.

DaniilM [7]

<span>Freezing involves the decrease in value of latent heat by 80 Cal/gm and a change of state from the Liquid phase to the solid phase.

So, in short, Fill in the blank as follows:
1st blank = Release/decrease
2nd blank = Liquid

Hope this helps!

</span>

7 0

2 years ago

The boat is travelling at a constant velocity.

raketka [301]

the friction forces are smaller than the forward force

5 0

3 years ago

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xxMikexx [17]

You should write meter per second square for the acceleration in words

7 0

3 years ago