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lianna [129]
3 years ago
8

What minerals can Talc scratch?

Physics
2 answers:
aleksandr82 [10.1K]3 years ago
6 0
<span>If it leaves a scratch, the mineral is softer than talc. If it doesn't, the mineral is harder than talc. Continue doing this with the harder standard minerals - gypsum, calcite and so on. If, for example, your mineral can be scratched by fluorite but not by calcite, it will have a hardness of about three and a half.
i copied this from a site so you'll get the answer BUT DONT ACTUALLY PUT THIS AS YOU ANSWER!
</span>
Viefleur [7K]3 years ago
5 0
None I believe... talc is a 1 on the Mohs Hard Scale and is the main ingredient in baby powder
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A 2.00-m long uniform beam has a mass of 4.00 kg. The beam rests on a fulcrum that is 1.20 m from its left end. In order for the
Shalnov [3]

Answer:

x ’= 1,735 m,  measured from the far left

Explanation:

For the system to be in equilibrium, the law of rotational equilibrium must be fulfilled.

Let's fix a reference system located at the point of rotation and that the anticlockwise rotations have been positive

             

They tell us that we have a mass (m1) on the left side and another mass (M2) on the right side,

the mass that is at the left end x = 1.2 m measured from the pivot point, the mass of the right side is at a distance x and the weight of the body that is located at the geometric center of the bar

           x_{cm} = 1.2 -1

          x_ {cm} = 0.2 m

          Σ τ = 0

          w₁ 1.2 + mg 0.2 - W₂ x = 0

          x = \frac{m_1 g\ 1.2 \ + m g \ 0.2}{M_2 g}

          x = \frac{m_1 \ 1.2 \ + m \ 0.2 }{M_2}

let's calculate

          x = \frac{2.9 \ 1.2 \ + 4 \ 0.2 }{8.00}2.9 1.2 + 4 0.2 / 8

           

          x = 0.535 m

measured from the pivot point

measured from the far left is

           x’= 1,2 + x

           x'=  1.2 + 0.535

           x ’= 1,735 m

8 0
3 years ago
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Please give an answer that is coherent
Semmy [17]

Answer:

480

Explanation:

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120÷0.25

=480

6 0
3 years ago
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Westkost [7]

Answer:

Yes, it is correct : )

Explanation:

Hope this helps!

8 0
3 years ago
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You are piloting a helicopter which is rising vertically at a uniform velocity of 14.70 m/s. When you reach 196.00 m, you see Ba
Cloud [144]

Answer:

The ball reaches Barney  head in  t = 8 \ s

Explanation:

From the question we are told that

 The rise velocity is  v  =  14.70 \  m/s

  The height considered is h =  196 \  m

   The horizontal velocity of the large object is  v_h  =  8.50 \  m/s

   

Generally from kinematic equation  

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Here s is the distance of the object from Barney head ,

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So  

     u = -14.7 m/s

So

    196  = -14.7 t  + \frac{1}{2} * 9.8 * t^2

=  4.9 t^2 - 14.7t - 196 = 0

Solving the above equation using quadratic formula  

    The value of  t obtained is  t = 8 \ s

6 0
3 years ago
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