I believe the answer is B. a million or more.
Answer:
D
Explanation:
The amount of energy released or absorbed is equal the product of the mass, the specific heat capacity and the temperature change. The temperature change being the difference between the final and initial temperature.
Q = mc∆T
Q = heat energy (Joules, J) m = mass of a substance (kg) c = specific heat (units J/g∙K)
∆ is a symbol meaning "the change in" ∆T = change in temperature (Kelvins, K)
From the data provided in the question, we can deduce that:
Q = 16.7KJ = 16,700J
m = 225g
c = 1.74J/g.k
For the temperature, let the final temperature be f. This means our ∆T = f - 20
16,700 = 225 * 1.74 * (f - 20)
16700 = 391.5 (f - 20)
f - 20 = 16700/391.5
f - 20 = 42.7
f = 20 + 42.7 = 62.7
Answer:
1.2* 10³ rNe.
Explanation:
Given speed of neon=350 m/s
Un-certainity in speed= (0.01/100) *350 =0.035 m/s
As per heisenberg uncertainity principle
Δx*mΔv ≥\frac{h}{4\pi }
4π
h
..................(1)
mass of neon atom =\frac{20*10^{-3} }{6.22*10^{-23} } =3.35*10^{-26} kg
6.22∗10
−23
20∗10
−3
=3.35∗10
−26
kg
substituating the values in eq. (1)
Δx =4.49*10^{-8}10
−8
m
In terms of rNe i.e 38 pm= 38*10^{-12}10
−12
Δx=\frac{4.49*10^{-8} }{38*10^{-12} }
38∗10
−12
4.49∗10
−8
=0.118*10^{4}10
4
* (rNe)
=1.18*10³ rN
= 1.2* 10³ rNe.
Explanation:
This is the answer
Answer:
0.5133805136 moles.
Explanation:
1 gram of Al2(Co3)3 equals 0.0017112683785004 moles, we need the amount of moles produced in 300 grams of Al2(CO3)3, so we have to multiply 1 gram of Al2(CO3)3 times 300: 0.0017112683785004 x 300, in conclusion,
300 grams of Al2(Co3)3 equals 0.5133805136.
The valence of helium is 0.
