Answer:
The depth of the lake is 67.164 meters.
Explanation:
The combined gas equation is,
where,
= initial pressure of gas in bubble= ?
= final pressure of gas = 0.980 atm
= initial volume of gas = 
= final volume of gas = 8.00 × V
= initial temperature of gas = 
= final temperature of gas = 
Now put all the given values in the above equation, we get:
pressure of the gas in bubble initially is equal to the sum of final pressure and pressure exerted by water at depth h.
Where :
density of water = 
g = acceleration due gravity = 
h = 67.164 m
The depth of the lake is 67.164 meters.
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Answer:
Explanation:
· 44 g NaCl Explanation: The problem provides you with the molarity and volume of the target
The answer is rounded to two sig figs, the number of sig figs you have for the molarity of the solution.
Answer:
The new volume of the sample is halved.
Explanation:
Data obtained from the question include the following:
Initial volume (V1) = V
Initial temperature (T1) = T
Initial pressure (P1) = P
Final pressure (P2) = quadrupled = 4P
Final temperature (T2) = doubled = 2T
Final volume (V2) =?
Thus, we can obtain the new volume of the same by using the combined gas equation as shown below:
P1V1 /T1 = P2V2 /T2
P × V/T = 4P × V2/2T
Cross multiply
T × 4P × V2 = P × V × 2T
Divide both side by T × 4P
V2 = (P × V × 2T) / (T × 4P)
V2 = V/2
V2 = ½V
Therefore, the new volume of the sample is halved .
CH4 is the molecular formula for methane.
