Answer:
V = 125.7m/min
Explanation:
Given:
L = 400 mm ≈ 0.4m
D = 150 mm ≈ 0.15m
T = 5 minutes
F = 0.30mm ≈ 0.0003m
To calculate the cutting speed, let's use the formula :
We are to find the speed, V. Let's make it the subject.
Substituting values we have:
V = 125.68 m/min ≈ 125.7 m/min
Therefore, V = 125.7m/min
Answer:
All 3 principal stress
1. 56.301mpa
2. 28.07mpa
3. 0mpa
Maximum shear stress = 14.116mpa
Explanation:
di = 75 = 0.075
wall thickness = 0.1 = 0.0001
internal pressure pi = 150 kpa = 150 x 10³
torque t = 100 Nm
finding all values
∂1 = 150x10³x0.075/2x0,0001
= 0.5625 = 56.25mpa
∂2 = 150x10³x75/4x0.1
= 28.12mpa
T = 16x100/(πx75x10³)²
∂1,2 = 1/2[(56.25+28.12) ± √(56.25-28.12)² + 4(1.207)²]
= 1/2[84.37±√791.2969+5.827396]
= 1/2[84.37±28.33]
∂1 = 1/2[84.37+28.33]
= 56.301mpa
∂2 = 1/2[84.37-28.33]
= 28.07mpa
This is a 2 d diagram donut is analyzed in 2 direction.
So ∂3 = 0mpa
∂max = 56.301-28.07/2
= 14.116mpa
Answer:
33.56 ft^3/sec.in
Explanation:
Duration = 6 hours
drainage area = 185 mi^2
constant baseflow = 550 cfs
<u>Derive the unit hydrograph using the inverse procedure </u>
first step : calculate for the volume of direct runoff hydrograph using the details in table 2 attached below
Vdrh = sum of drh * duration
= 29700 * 6 hours ( 216000 secs )
= 641,520,000 ft^3.
next step : Calculate the volume of runoff in equivalent depth
Vdrh / Area = 641,520,000 / 185 mi^2
= 1.49 in
Finally derive the unit hydrograph
Unit of hydrograph = drh / volume of runoff in equivalent depth
= 50 ft^3 / 1.49 in = 33.56 ft^3/sec.in
Answer:
a) V(t) = Ldi(t)/dt
b) If current is constant, V = 0
Explanation:
a) The voltage, V(t), across an inductor is proportional to the rate of change of the current flowing across it with time.
If V represents the Voltage across the inductor
and i(t) represents the current across the inductor in time, t.
V(t) ∝ di(t)/dt
Introducing a proportionality constant,L, which is the inductance of the inductor
The general equation describing the voltage across the inductor of inductance, L, as a function of time when a current flows through it is shown below.
V(t) = Ldi(t)/dt ..................................................(1)
b) If the current flowing through the inductor is constant i.e. does not vary with time
di(t)/dt = 0 and hence the general equation (1) above becomes
V(t) = 0
