Answer:
a) benzene = 910 days
b) toluene = 1612.67 days
Explanation:
Given:
Kd = 1.8 L/kg (benzene)
Kd = 3.3 L/kg (toluene)
psolid = solids density = 2.6 kg/L
K = 2.9x10⁻⁵m/s
pores = n = 0.37
water table = 0.4 m
ground water = 15 m
u = K/n = (2.9x10⁻⁵ * (0.4/15)) / 0.37 = 2.09x10⁻⁶m/s
a) For benzene:
![R=1+\frac{\rho * K_{d} }{n}, \rho = 2.6\\ R=1+\frac{2.6*1.8}{0.37} =13.65](https://tex.z-dn.net/?f=R%3D1%2B%5Cfrac%7B%5Crho%20%2A%20K_%7Bd%7D%20%20%7D%7Bn%7D%2C%20%5Crho%20%3D%202.6%5C%5C%20R%3D1%2B%5Cfrac%7B2.6%2A1.8%7D%7B0.37%7D%20%3D13.65)
The time will take will be:
![t=\frac{xR}{a} , x=12,a=0.18\\t=\frac{12*13.65}{0.18} =910days](https://tex.z-dn.net/?f=t%3D%5Cfrac%7BxR%7D%7Ba%7D%20%2C%20x%3D12%2Ca%3D0.18%5C%5Ct%3D%5Cfrac%7B12%2A13.65%7D%7B0.18%7D%20%3D910days)
b) For toluene:
![R=1+\frac{2.6*3.3 }{0.37} = 24.19](https://tex.z-dn.net/?f=R%3D1%2B%5Cfrac%7B2.6%2A3.3%20%20%7D%7B0.37%7D%20%3D%2024.19)
![t=\frac{12*24.19}{0.18} =1612.67days](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B12%2A24.19%7D%7B0.18%7D%20%3D1612.67days)
Answer:
VR Prototyping
VR Prototyping Can Save you Thousands of Dollars.
Explanation:
there you go lad
Answer:
the difference in pressure between the inside and outside of the droplets is 538 Pa
Explanation:
given data
temperature = 68 °F
average diameter = 200 µm
to find out
what is the difference in pressure between the inside and outside of the droplets
solution
we know here surface tension of carbon tetra chloride at 68 °F is get from table 1.6 physical properties of liquid that is
σ = 2.69 ×
N/m
so average radius =
= 100 µm = 100 ×
m
now here we know relation between pressure difference and surface tension
so we can derive difference pressure as
2π×σ×r = Δp×π×r² .....................1
here r is radius and Δp pressure difference and σ surface tension
Δp =
put here value
Δp =
Δp = 538
so the difference in pressure between the inside and outside of the droplets is 538 Pa
Given acceleration a = 5-3t, and its velocity is 7 at time t = 2, the value of s2 - s1 = 7
<h3>How to solve for the value of s2 - s1</h3>
We have
= ![\frac{dv}{dt} =v't = 5-3t\\\\\int\limits^a_b {v'(t)} \, dt](https://tex.z-dn.net/?f=%5Cfrac%7Bdv%7D%7Bdt%7D%20%3Dv%27t%20%3D%205-3t%5C%5C%5C%5C%5Cint%5Climits%5Ea_b%20%7Bv%27%28t%29%7D%20%5C%2C%20dt)
![= \int\limits^a_b {(5-3t)} \, dt](https://tex.z-dn.net/?f=%3D%20%5Cint%5Climits%5Ea_b%20%7B%285-3t%29%7D%20%5C%2C%20dt)
![5t - \frac{3t^2}{2} +c](https://tex.z-dn.net/?f=5t%20-%20%5Cfrac%7B3t%5E2%7D%7B2%7D%20%2Bc)
v2 = 5x2 - 3x2 + c
= 10-6+c
= 4+c
![s(t) = \frac{5t^2}{2} -\frac{t^3}{2} +3t + c](https://tex.z-dn.net/?f=s%28t%29%20%3D%20%5Cfrac%7B5t%5E2%7D%7B2%7D%20-%5Cfrac%7Bt%5E3%7D%7B2%7D%20%2B3t%20%2B%20c)
S2 - S1
![=(5*\frac{4}{2} -\frac{8}{2} +3*2*c)-(\frac{5}{2} *1^2-\frac{1^2}{2} +3*1*c)](https://tex.z-dn.net/?f=%3D%285%2A%5Cfrac%7B4%7D%7B2%7D%20-%5Cfrac%7B8%7D%7B2%7D%20%2B3%2A2%2Ac%29-%28%5Cfrac%7B5%7D%7B2%7D%20%2A1%5E2-%5Cfrac%7B1%5E2%7D%7B2%7D%20%2B3%2A1%2Ac%29)
= 6 + 6+c - 2+3+c
12+c-5+c = 0
7 = c
Read more on acceleration here: brainly.com/question/605631
What the given passage is saying about the relationship between sustainability and responsibility is that;
C: We should only consider products or services to be green if their broad impact can be considered so.
<h3>Sustainability</h3>
From the passage, we see a write up questioning if the things we term to be green are truly green.
Now, from the passage, we see that a biofuel that is considered to be green is not really green if we consider that if it requires massive overproduction, it could wreck the water table.
Also, he says that if the production is local but also wasteful then it is not green.
Thus, we can see clearly that before we term a product or service as green, we should also consider their broad impact on the environment.
Read more about sustainability at; brainly.com/question/14154063