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sineoko [7]
3 years ago
7

Two particles, one with charge -5.45 × 10^-6 C and one with charge 4.39 × 10^-6 C, are 0.0209 meters apart. What is the magnitud

e of the force that one particle exerts on the other? Two new particles, which have identical positive charge q3, are placed the same 0.0209 meters apart, and the force between them is measured to be the same as that between the original particles. What is q3?
Physics
1 answer:
Levart [38]3 years ago
3 0

Explanation:

Given that,

Charge 1, q_1=-5.45\times 10^{-6}\ C

Charge 2, q_2=4.39\times 10^{-6}\ C

Distance between charges, r = 0.0209 m

1. The electric force is given by :

F=k\dfrac{q_1q_2}{r^2}

F=9\times 10^9\times \dfrac{-5.45\times 10^{-6}\times 4.39\times 10^{-6}}{(0.0209)^2}

F = -492.95 N

2. Distance between two identical charges, r=0.0209\ m

Electric force is given by :

F=\dfrac{kq_3^2}{r^2}

q_3=\sqrt{\dfrac{Fr^2}{k}}

q_3=\sqrt{\dfrac{492.95\times (0.0209)^2}{9\times 10^9}}

q_3=4.89\times 10^{-6}\ C

Hence, this is the required solution.

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An air-filled parallel-plate capacitor is constructed with a plate area of 0.40 m2 and a plate separation of 0.10 mm. It is then
seropon [69]

Answer:

The charge stored  is  Q =  4.25 *10^{-7 } \ C

The energy stored is  E = 2.55*10^{-6} \ J

Explanation:

From the question we are told that

    The area of the plates is  A =  0.40 \ m^2

     The separation between the plate is d =  0.10 \ mm =0.0001 \ m

      The potential difference is  V =  12 \ V

       The permitivity of free space is  \epsilon_o  = 8.85 *10^{-12} C^2 \cdot N^{-1} \cdot m^2

         The dielectric constant of glass is K =  5.0

Generally the capacitance of this capacitor is

      C =  \frac{\epsilon_o  * A}{d}

substituting values

       C =  \frac{8.85*10^{-12}  * 0.40}{0.0001}

        C =   3.34 *10^{-8} \ C

The charge stored is mathematically evaluated as

         Q = CV

substituting values

        Q =  (3.54*10^{-8} * 12)

         Q =  4.25 *10^{-7 } \ C

The energy stored is  

         E =  0.5 *  CV^2

substituting values

         E =  0.5 *  (4.25 *10^{-7} * 12^2)

           E = 2.55*10^{-6} \ J

7 0
3 years ago
What is one advantage of using primary sources when doing research on an
WITCHER [35]

One advantage of using primary sources when doing research on an experiment is, it contain more details about the experiment. Thus, option D is right .

To find the answer, we have to know more about the Primary sources.

<h3>What is the advantages of primary sources?</h3>
  • Primary sources are the direct or first-hand excerpts that scientists have independently written based on their experiments in order to support their research.
  • Utilizing original sources encourages analytical and critical thought in relation to the research.
  • It aids in exploring from various angles, which leads to the discovery of extra facts.
  • Primary data aids in navigating the conflicts. Since it is a direct resource related to the experiment, it serves as evidence for the data.

Thus, we can conclude that, Primary sources contain more details about the experiment.

Learn more about the Primary sources here:

brainly.com/question/24190082

#SPJ9

5 0
1 year ago
1 ) Starting from rest, a toy rocket accelerates at 12 m/sec/sec for exactly 4.0 seconds. It reaches 48 m/sec. Find the distance
dusya [7]
Displacement equals (Velocity times Time) plus half times the (acceleration times time squared). =. (48 * 4) + 1/2 * (12 *12^2) = 288meters
3 0
3 years ago
What is the weight of an object when the object has a mass of 22kg
Savatey [412]
Assuming the object is on earth the objects weight would be equal to its mass multiplied by the gravitational field constant

mass=22kg
g=9.80665N/kg

weight=(22 kg) (9.80665 N/kg)=215.7463N

generally g is rounded to be 10 N/kg so for any question where it asks the weight given the mass just multiply by 10 and that should suffice. In this case the answer would be 220 N
5 0
3 years ago
Someone please help with this
SSSSS [86.1K]

Answer:

<em>The new force is 2/3 of the original force</em>

Explanation:

<u>Coulomb's Law </u>

The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the objects' charge

d= The distance between the objects

Suppose the first charge is doubled (2q1) and the second charge is one-third of the original charge (q2/3). Now the force is:

\displaystyle F'=k\frac{2q_1*q_2/3}{d^2}

Factoring out 2/3:

\displaystyle F'=\frac{2}{3}k\frac{q_1*q_2}{d^2}

Substituting the original force:

F'=\frac{2}{3}F

The new force is 2/3 of the original force

7 0
3 years ago
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