Answer:
あなたのポイントを無駄にして申し訳ありませんが、あなたの質問がその言語を日本語にすることがわかりません
hey guy
the vibration per second is frequency
then for 20 vibration time taken is 100 second
in 1 second 20/100 vibration took place
it means 0.2 is frequency
for time period , we have
t=1/f
=1/0.2
=5
<span>Falcon 9</span><span>Pegasus</span><span>Proton</span><span><span>Satellite </span><span>Launch </span>Vehicle</span><span>Antares</span><span>Zenit</span><span>Atlas V</span><span>Soyuz</span><span>Ariane 5</span><span>Delta IV</span><span><span>Polar Satellite </span><span>Launch </span>Vehicle</span><span><span>Geosynchronous </span><span>Satellite </span>Launch Vehicle</span><span>Vega</span><span>Rokot</span><span>Angara</span><span>Soyuz-2</span><span>Shavit</span><span>H-IIB</span><span>Dnepr</span><span>Safir</span><span>Falcon 1</span><span><span>Long March </span>4B</span><span><span>Long March </span>2D</span><span>Delta II</span><span>H-II</span><span><span>Long March </span>3C</span><span>Soyuz-U</span><span><span>Long March </span>4C</span><span>Black Arrow</span><span><span>Long March </span>3A</span><span>Naro-1</span><span>Zenit-3SL</span><span>Sputnik</span><span><span>Long March </span>2F</span><span>VLS-1</span><span>Vulcan</span><span><span>Long March </span>2C</span><span>Athena</span><span><span>Long March </span>3B</span><span>Juno I</span><span>N1</span><span>Ariane 6</span><span>Kuaizhou</span><span>Zenit-2</span><span>Simorgh</span><span><span>Long March </span>11</span><span>Strela</span><span>Minotaur-C</span><span>Ariane 1</span><span><span>Augmented </span><span>Satellite </span>Launch Vehicle</span><span>Europa<span>
</span></span>
Explanation:
Below is an attachment containing the solution.
Answer:
I = 4.38 x 10⁻⁷ A
Explanation:
Given,
speed = 4.47 x 10⁴ m/s
radius of the circular path, r = 2.59 x 10⁻⁹ m
effective current = ?
The current represented by the orbiting electron is equal to
f is the frequency
q is charge of electron
we know,
f = 2.74 x 10¹² Hz
now,
I = 4.38 x 10⁻⁷ A
Hence, the effective current associated with the orbiting electron is equal to I = 4.38 x 10⁻⁷ A
