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Contact [7]
3 years ago
11

If the atoms and molecules of a substance are moving very fast, the substance is _________.

Physics
2 answers:
lana66690 [7]3 years ago
5 0
A. hot is the correct answer.
Hope it helps!
Furkat [3]3 years ago
3 0
<span>If the atoms and molecules of a substance are moving very fast, the substance is _________.

a) hot
 The temperature is droping, the movements are slowly
At minus 273 Celsius (0 Kelvin) there is no movement</span>
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A circuit is built based on the circuit diagram shown. What is the current in the 50 Ω resistor
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Answer:

1.2 A

Explanation:

From the diagram attached, The three resistors are parallel because the each ends of the resistors are connected together. Since they are in parallel, the voltage across each resistor is the same. The voltage source connected in parallel to the resistors is 60 V. Therefore the voltage across the 50 Ω resistor is 60 V. Using ohm law:

Voltage (V) = Current (I) × Resistance (R)

V = IR

I = V/R

I = 60 V/ 50 Ω

I = 1.2 A

The current in the 50 Ω resistor is 1.2 A

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the rock of 10 kg is falling near the Earth's surface.assume that g =10N/kg and the is no air resistance. what is the accelerati
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3 years ago
Formula for percentage error​
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PE = (|accepted value – experimental value| \ accepted value) x 100%

Explanation:

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Which planet has the GREATEST attraction to the sun?
AveGali [126]
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3 years ago
In a thin film experiment, a wedge of air is used between two glass plates. If the wavelength of the incident light in air is 48
cluponka [151]

Answer:

The thickness is  \Delta y =  2.4 *10^{-6} \  m

Explanation:

From the question we are told that

   The wavelength is  \lambda  = 480 \ nm = 480*10^{-9} \  m

    The first order of the dark  fringe is  m_1 =  16

     The second order of dark fringe considered is  m_2 = 6

Generally the condition for destructive interference is mathematically represented as

        y = \frac{m \lambda}{2}

Here y is the path difference between the central maxima(i.e the origin) and any dark fringe

So  the path difference between the 16th dark fringe and the 6th dark fringe is mathematically represented as

      y_1 - y_2 = \Delta y =  \frac{m_1 \lambda}{2} -  \frac{m_2 \lambda}{2}

=>  y_1 - y_2 = \Delta y =  \frac{16 *480*10^{-9}}{2} -  \frac{6 *480*10^{-9}}{2}

=>  y_1 - y_2 = \Delta y =  5 (480*10^{-9})

=>  \Delta y =  2.4 *10^{-6} \  m

8 0
3 years ago
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