Answer:
<h3>The answer is 15 N</h3>
Explanation:
The force acting on an object can be found by using the formula
<h3>Force = mass × acceleration</h3>
From the question
mass = 50 g = 0.05 kg
acceleration = 300 m/s²
We have
force = 0.05 × 300
We have the final answer as
<h3>15 N</h3>
Hope this helps you
Answer:
To calculate the tension on a rope holding 1 object, multiply the mass and gravitational acceleration of the object. If the object is experiencing any other acceleration, multiply that acceleration by the mass and add it to your first total.
Explanation:
The tension in a given strand of string or rope is a result of the forces pulling on the rope from either end. As a reminder, force = mass × acceleration. Assuming the rope is stretched tightly, any change in acceleration or mass in objects the rope is supporting will cause a change in tension in the rope. Don't forget the constant acceleration due to gravity - even if a system is at rest, its components are subject to this force. We can think of a tension in a given rope as T = (m × g) + (m × a), where "g" is the acceleration due to gravity of any objects the rope is supporting and "a" is any other acceleration on any objects the rope is supporting.[2]
For the purposes of most physics problems, we assume ideal strings - in other words, that our rope, cable, etc. is thin, massless, and can't be stretched or broken.
As an example, let's consider a system where a weight hangs from a wooden beam via a single rope (see picture). Neither the weight nor the rope are moving - the entire system is at rest. Because of this, we know that, for the weight to be held in equilibrium, the tension force must equal the force of gravity on the weight. In other words, Tension (Ft) = Force of gravity (Fg) = m × g.
Assuming a 10 kg weight, then, the tension force is 10 kg × 9.8 m/s2 = 98 Newtons.
Answer:
False
Explanation:
Becuase the average amu of 40 is represented
Answer:
180° C
Explanation:
First we start by finding the area of the stopper.
A = πd²/4, where d = 1.5 cm = 0.015 m
A = 3.142 * 0.015² * ¼
A = 1.767*10^-4 m²
Next we find the force on the stopper
F = (P - P•)A, where
F = 10 N
P = pressure inside the tube,
P• = 1 atm
10 = (P - 101325) * 1.767*10^-4
P - 101325 = 10/1.767*10^-4
P - 101325 = 56593
P = 56593 + 101325
P = 157918 Pascal
Now, remember, in an ideal gas,
P1V1/T1 = P2V2/T2, where V is constant, then we have
P1/T1 = P2/T2, and when we substitute the values, we have
101325/(273 + 18) = 157918/ T2
101325/291 = 157918/ T2
T2 = (157918 * 291)/101325
T2 = 453 K
T2 = 453 - 273 = 180° C
