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charle [14.2K]
3 years ago
10

Platinum has a work function (also called binding energy) of 9.05 × 10-19 J. Which is the longest wavelength that could cause em

ission of electrons? 2.196 × 106 m 5.654 × 102 m 2.196 × 10-7 m 1.37 × 1015 m 4.553 × 10-6 m
Physics
1 answer:
son4ous [18]3 years ago
6 0

Answer:

2,196 10⁻⁷ m

Explanation:

This is a problem of photoelectric effect, which was explained by Einstein, assuming that the light was formed by quanta of energy that collide with the electors and is described by the expression

         K_{max} = h f -Ф

Where   K_{max} is the maximum kinetic energy of the expelled electrons h is the Planck constant that is worth 6,626 10-34 J s, f is the radiation frequency and Ф is the material's work function.

For the wavelength of greater wavelength (lower energy) the kinetic energy of the electors must decrease to a minimum of zero.

         0 = hf -Ф

         hf = Ф

         f = Ф / h

         f = 9.05 10-19 / 6,626 10-34

         f = 1,366 10 15 Hz

Now the speed of the wave is related to the wavelength and frequency

        c = λ f

        λ = c / f

        λ = 3 10⁸ / 1,366 10¹⁵

        λ = 2,196 10⁻⁷ m

The result is 2,196 10⁻⁷ m

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Determine if the data are qualitative or quantitative.
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Qualitative, Quantitative, Qualitative, Quantitative, and Qualitative.

Explanation:

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Merry-go-rounds are a common ride in park playgrounds. The ride is a horizontal disk that rotates about a vertical axis at their
Vera_Pavlovna [14]

Answer:

A = 2.36m/s

B = 3.71m/s²

C = 29.61m/s2

Explanation:

First, we convert the diameter of the ride from ft to m

10ft = 3m

Speed of the rider is the

v = circumference of the circle divided by time of rotation

v = [2π(D/2)]/T

v = [2π(3/2)]/4

v = 3π/4

v = 2.36m/s

Radial acceleration can also be found as a = v²/r

Where v = speed of the rider

r = radius of the ride

a = 2.36²/1.5

a = 3.71m/s²

If the time of revolution is halved, then radial acceleration is

A = 4π²R/T²

A = (4 * π² * 3)/2²

A = 118.44/4

A = 29.61m/s²

7 0
3 years ago
A steel pipe of 12-in. outer diameter is fabricated from 1 4 -in.-thick plate by welding along a helix that forms an angle of 25
Varvara68 [4.7K]

Answer:

Normal stress = 66/62.84 = 1.05kips/in²

shearing stress  = T/2 = 0.952/2 = 0.476 kips/in²

Explanation:

A steel pipe of 12-in. outer diameter  d₂ =12in  d₁= 12 -4in = 8in

4 -in.-thick  

angle of 25°

Axial force P = 66 kip axial force

determine the normal and shearing stresses

Normal stress б = force/area = P/A

           = 66/ (П* (d₂²-d₁²)/4

           =66/ (3.142* (12²-8²)/4

          = 66/62.84 = 1.05kips/in²

Tangential stress T = force* cos ∅/area = P/A

           = 66* cos 25/ (П* (d₂²-d₁²)/4

           =59.82/ (3.142* (12²-8²)/4

          = 59.82/62.84 = 0.952kips/in²

shearing stress  = tangential stress /2

                           = T/2 = 0.952/2 = 0.476 kips/in²

8 0
3 years ago
A sample of chloroform is found to contain 12.0 g of carbon, 106.4 g of chlorine, and 1.01 g of hydrogen. If a second sample of
GREYUIT [131]

Given:

Sample 1:

Chloroform is CHCl_{3}

12 g Carbon

1.01 g Hydrogen

106.4 g Cl

Sample 2:

30.0 g of Carbon

Solution:

mass of chloroform from sample 1:

12 + 1.01 +106.4 =119.41 g

Now, for the total mass of chloroform in sample 2:

mass of chloroform \times\frac{given mass of carbon}{mass of carbon atom}

mass of chloroform = 119.41 \times\frac{30}{12} = 298.53 g

6 0
3 years ago
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