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ICE Princess25 [194]
4 years ago
8

Larry drives 20.0 km to the east from his house then 20.0 km west back to his house, takes 5.0 mins to find his wallet and leave

s again. Larry is 40.0 km east of his house 60.0 mins after he left the first time.
A) what is his avg. velocity?

B) what is his avg. speed?
Physics
1 answer:
Scorpion4ik [409]4 years ago
4 0

Larry's average speed is 
                                       (total distance) / (total time).

                      Speed = (80 km) / (60 min) = 80 km/hr .


Larry's average velocity is  
                                         (distance between start- and end- points),
                                  in the direction from the start-point to the end-point.

                       Velocity = (40 km east) / (60 min) = 40 km/hr east .

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To solve this question, we will use the law of conservation of kinetic and potential energy, which is given by the equation,

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In this question, it is safe to say there is no kinetic energy in the initial state, and neither is there potential energy in the end, so we have

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To calculate the final kinetic energy, we must consider the energy contributed by the Inertia, so that we then have

mgh = 1/2mv² + 1/2Iw²

To get the inertia of the bodies, we use the formula

I = [m(R1² + R2²) / 2]

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Also, the angular velocity is given by

w = v / R2

w = 4 / (1/5)

w = 20 rad/s

If we then substitute these values in the equation we have,

0.5 * 9.8 * h = (1/2 * 0.5 * 4²) + (1/2 * 0.05 * 20²)

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<h3>What is an energy chain diagram?</h3>

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Chemical energy (in this case, the fuel of the car) is a type of energy that is stored to perform work.

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From the question given above, the following data were obtained:

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Momentum is denoted by P.

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<h3>Given:</h3>

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