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Svet_ta [14]
3 years ago
15

Matter with a density that is less than water will____ when placed in a container of water?

Physics
1 answer:
lorasvet [3.4K]3 years ago
7 0

Answer:

float

Explanation:

a less dense material will float when placed in a material that is more dense than itself. The reverse is also true, that a denser material will sink when placed into into a less dense material.

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Which of the following is a theory stating that one plate is forced beneath another plate?
morpeh [17]

Answer:

theroy of plate tectonics

7 0
3 years ago
when do you use cos and sin in situations like these? is horizontal always cos and vertical always sin?
Andreas93 [3]

Answer:

yes

Explanation:

this is simple

the horizontal line is adjacent

the vertical line is opposite

recall that cos x=adj/hyp

adj=hyp(cos x)

while opp=hyp(sin x)

8 0
3 years ago
Which statement about two objects having the same momentum is true?
Reil [10]

Answer:

The product of mass X velocity is the same for both

Explanation:

The momentum of a body is the product of its mass and velocity.

  Momentum  = mass x velocity

Two objects having equal momentum will have the same for the product of their mass and velocity.

  • It is amount of motion a body can produce.
7 0
3 years ago
A crate lies on a plane tilted at an angle θ = 22.5 ∘ to the horizontal, with μk = 0.19.
ValentinkaMS [17]

A) 2.03 m/s^2

Let's start by writing the equation of the forces along the directions parallel and perpendicular to the incline:

Parallel:

mg sin \theta - \mu_k R = ma (1)

where

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

\theta=22.5^{\circ}

\mu_k = 0.19 is the coefficient of friction

R is the normal reaction

a is the acceleration

Perpendicular:

R-mg cos \theta =0 (2)

From (2) we find

R=mg cos \theta

And substituting into (1)

mg sin \theta - \mu_k mg cos \theta = ma

Solving for a,

a=g sin \theta - \mu_k g cos \theta = (9.8)(sin 22.5)-(0.19)(9.8)(cos 22.5)=2.03 m/s^2

B) 5.94 m/s

We can solve this part by using the suvat equation

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

Here we have

v = ?

u = 0 (it starts from rest)

a=2.03 m/s^2

s = 8.70 m

Solving for v,

v=\sqrt{u^2+2as}=\sqrt{0+2(2.03)(8.70)}=5.94 m/s

6 0
3 years ago
A car speeds up from 12.0 m/s to 16.0 m/s in 8.00s what is the acceleration
Lerok [7]

Answer:

0.5m/s²

Explanation:

acceleration =v-u/t

=(16-12)/8

=4/8

acceleration =0.5m/s²

7 0
3 years ago
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