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asambeis [7]
4 years ago
13

What is the name of the space telescope in low earth orbit that was launched in 1990?

Physics
1 answer:
Mrrafil [7]4 years ago
4 0

The Hubble Space Telescope is a joint ESA/NASA project and was launched in 1990 by the Space Shuttle mission STS-31 into a low-Earth orbit 569 km above the ground. During its lifetime Hubble has become one of the most important science projects ever. Hope this helps! ~ Autumn :)

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Evaporates can provide an ideal speed racing surface.<br><br> True<br> or <br> False
musickatia [10]

the answer is true because evaporates can provide an ideal speed racing surface


6 0
3 years ago
A car has an acceleration of 1.5 m/s2. A net force of 2100 N is acting on the car. What is the mass of the car?
gulaghasi [49]

Answer:

Given

acceleration (a) =1.5ms2

Force(F) =2100N

R. t. c mass (m) =?

Form

F=ma(divided by m both sides)

m=F/a

m=2100/105

m=1400kg

mass of car =1400kg

8 0
3 years ago
At one instant, an object moving downward in free fall on the Earth has a speed of 50 m/s. Its speed 1 second later is
maksim [4K]

Answer:

velocity 1 second later = 59.8 m/s

Explanation:

Velocity final = Velocity initial + acceleration • time

Velocity final = 50m/s + 9.8m/s/s • 1s

Velocity final = 59.8 m/s

4 0
2 years ago
Why is it important to study electromagnetic waves?
labwork [276]
The study of EM is essential to understanding the properties of light, its propagation through tissue, scattering and absorption effects, and changes in the state of polarization. ... Since light travels much faster than sound, detection of the reflected EM radiation is performed with interferometry.
3 0
3 years ago
When 2.00 kJ of energy is transferred as heat to nitrogen in a cylinder fitted with a piston with an external pressure of 2.00 a
julia-pushkina [17]

Answer:

ΔU= 1.3922 KJ

Explanation:

Given that

Q= 2 KJ  

Note- 1 .Heat added to the system taken as positive and heat leaving from the system is taken negative.

2. Work done on the system taken as negative and work done by the system taken as positive.

P =2 atm

V₁= 2 L

V₂=5 L

Work done by the gas W

W= P ( V₂- V₁)

W= 2 ( 5 - 2)

W= 6 atm.L

1 L·atm = 0.1013 kJ

W= 0.6078 KJ

From first law of thermodynamics

Q= W + ΔU

ΔU=Change in internal energy

2 = 0.6078 +  ΔU

ΔU= 1.3922 KJ

3 0
3 years ago
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