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Arisa [49]
3 years ago
5

Which of the following is an accurate statement about vectors?

Physics
2 answers:
MissTica3 years ago
5 0
<h3><u>Answer;</u></h3>

The magnitude of a vector may be positive even if all of its components are negative.

<h3><u>Explanation</u>;</h3>
  • Two vectors are equal if they have the same magnitude and the same direction. If two vectors have the same magnitude (size) and the same direction, then we call them equal to each other.
  • A negative vector is a vector that has the opposite direction to the reference positive direction.
  • When vectors are added, we take into account both their magnitudes and directions.
4vir4ik [10]3 years ago
5 0

<u>Answer:</u><u> </u>The magnitude of a vector may be positive even if all of its components are negative.

<u>Explanation:</u>

A vector has both magnitude and direction unlike a scalar which has magnitude only.

A vector can be written in terms of its components:

\vec{a} = a_x\hat{i}+a_y\hat{j}+a_z\hat{k}

The magnitude of the vector is given by:

|a| =\sqrt{a_x^2+a_y^2+a_z^2}

Thus, even if all the components of the vector are negative, the vector can have a positive magnitude.

The magnitude would be non-zero if one of its components is non-zero.

some of two vectors involves summation of magnitudes of of the vector components in the same direction. Two vectors having unequal magnitudes cannot have vector sum zero.

Rotating a vector about an axis passing through the tip of the vector changes the vector as the direction changes.

A scalar quantity cannot be added to a vector as it lacks the direction.

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Train cars are coupled together by being bumped into one another. Suppose two loaded cars are moving toward one another, the fir
tia_tia [17]

Answer:

7560 Joules

Explanation:

m_1 = Mass of first car = 1.5\times 10^5\ kg

m_2 = Mass of second car = 2\times 10^5\ kg

u_1 = Initial Velocity of first car = 0.3 m/s

u_2 = Initial Velocity of second car = -0.12 m/s

v = Velocity of combined mass

As linear momentum of the system is conserved

m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow v=\frac{1.5\times 10^5\times 0.3 + 2\times 10^5\times -0.12}{1.5\times 10^5 + 2\times 10^5}\\\Rightarrow v=0.06\ m/s

Energy lost is

\Delta E=\Delta E_i-\Delta E_f\\\Rightarrow \Delta=\frac{1}{2}(m_1u_1^2 + m_2u_2^2-(m_1+m_2)v^2)\\\Rightarrow \Delta=\frac{1}{2}(1.5\times 10^5\times 0.3^2 + 2\times 10^5\times (-0.12)^2-(1.5\times 10^5 + 2\times 10^5)\times 0.06^2)\\\Rightarrow \Delta=7560\ J

The Energy lost in the collision is 7560 Joules

7 0
3 years ago
What is the name of the small early planets, which formed through gravitational attraction reaching sizes of a few miles to even
Svetradugi [14.3K]

Answer:

Planetesimals  (Ex, Mercury, Venus , Mars & Earth)

Explanation:

They are known as Planetesimals , They are small in size and have rocky surface. The examples of Planetesimals  are Mercury, Venus Mars and Earth.

They are small early planets , which also has gravitational attraction.

Thanks

6 0
3 years ago
A stone is dropped from a cliff and falls 9.44 meters. What is the speed of the stone when it reaches the ground?
Lunna [17]

Answer:

option A

Explanation:

given,                                              

height of the drop of stone = 9.44 m

speed of the stone = ?                          

As the stone is dropped the energy of the stone will be conserved.

using conservation of energy.            

Potential energy = Kinetic energy    

m g h = \dfrac{1}{2} m v^2  

     v = \sqrt{2gh}                  

     v = \sqrt{2\times 9.8 \times 9.44}

     v = \sqrt{185.024}              

            v = 13.60 m/s                      

Hence, the correct answer is option A

3 0
3 years ago
___________ are over 500 million years old and have been developing their unique system all that time.
zhannawk [14.2K]

Answer:

C

Explanation:

3 0
3 years ago
Read 2 more answers
A delivery truck leaves a warehouse and travels 2.60 km north. The truck makes a left turn and travels 1.25 km west before makin
yulyashka [42]

Answer:

4.19 km and 107.35 degrees north of east

Explanation:

So in the end, the truck is (2.6 + 1.4 = 4km) north and 1.25 km west from the warehouse. We can use the Pythagorean formula to calculate the magnitude and direction α of the truck displacement from the warehouse:

s = \sqrt{s_n^2 + s_w^2} = \sqrt{4^2 + 1.25^2} = \sqrt{16 + 1.5625} = \sqrt{17.5625} = 4.19 km

tan\alpha = \frac{s_n}{s_w} = \frac{4}{1.25} = 3.2

\alpha = tan^{-1}3.2 = 1.27 rad \approx 72.65 degrees north or west or (180 - 72.65) = 107.35 degrees north of east

3 0
3 years ago
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