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bezimeni [28]
3 years ago
9

Humans and animals alike have critical periods of development.true false

Physics
2 answers:
Ilya [14]3 years ago
5 0
True, both humans and animals alike do have critical periods of development
geniusboy [140]3 years ago
5 0

Answer: True

Explanation:

Human beings and animals both have their critical time period of development and if they fail to learn things at that time then they fail to learn it for the rest of their life.

The development period of the animals and human beings starts after the birth when a person starts learning and development.

Example:  If a bird does not learns to sing at the critical periods then it will not learn it the whole life.

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A pesticide kills insects by disabling the ribosomes in their cells.
Stolb23 [73]

Answer:

cell division

7 0
3 years ago
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Which of the following is a negatively charged particle that is found in "clouds" around the nucleus?
shutvik [7]
The answer is electron



Explanation: An atom consists of a small but massive nucleus that include protons (positive charge) and neutrons (neutral charge). around the nucleus is a cloud of rapidly moving electrons (negative charge)
3 0
3 years ago
The particles ejected from the sun during a coronal mass ejection is called
ipn [44]

Answer:

Plasma

Explanation:

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The outermost part of the sun's atmosphere is called the Solar Corona Although difficult to see, the corona can be seen during a total solar eclipse.

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7 0
3 years ago
How is the number 3450 written in scientific notation?
sammy [17]

Answer:

B. 3.45 x 10^3

Explanation:

3450 = 3.45 \times  {10}^{3}  \\

4 0
4 years ago
A car drives around a curve with radius 539 m at a speed of 32.0 m/s. The road is banked at 5.00°. The mass of the car is 1.40 ×
HACTEHA [7]

Answer:

f_r = 150.47 N

Explanation:

given,

r = 539 m

v = 32 m/s

road banked at = 5°

∑ F_x

\dfrac{mv^2}{r}= N sin \theta + f_r cos \theta

∑ F_y = 0

0 = N cos \theta - f_r sin \theta - mg

N = \dfrac{f_rsin \theta + mg}{cos \theta}

\dfrac{mv^2}{r}= (\dfrac{f_rsin \theta + mg}{cos \theta})sin \theta + f_r cos \theta

              = f_r sin \theta tan \theta + mg tan \theta + f_r cos \theta

        f_r = \dfrac{\dfrac{mv^2}{r}- mg tan\theta}{sin\theta tan \theta + cos \theta}

         f_r = \dfrac{\dfrac{1.4\times 10^3 \times 32^2}{539}- 1.4\times 10^{3}\times 9.8 \times 0.087}{0.087 \times 0.087 + 0.996}

f_r = 150.47 N

8 0
3 years ago
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