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natka813 [3]
3 years ago
11

Which formula correctly shows how to calculat the time taken, given the average velocity and the displacement

Physics
1 answer:
Alisiya [41]3 years ago
8 0
We're so good here on Brainly, we can answer it
even WITHOUT seeing the choices.

     Time = (displacement) / (magnitude of average velocity) .
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Which example describes a norenewable resource
Sergeeva-Olga [200]

Answer: An example of a non-renewable would be oil.

Explanation:

All fossil fuels are nonrenewable, but not all nonrenewable energy sources are fossil fuels. Coal, crude oil, and natural gas are all considered fossil fuels

8 0
3 years ago
A kid pulls on a rope with 20 newtons of force. The block and tackle system pulls up a 160 newton box. What is the mechanical ad
Minchanka [31]
Answer:
The mechanical advantage of the system is 8

Explanation:
the mechanical advantage measures how much the system multiplies the input force to get the output.

In the given:
The input force (effort) is 20 Newton
The output force (load) is 160 Newton

This means that the mechanical advantage is:
mechanical advantage = load / effort = 160 / 20 = 8

Note that the mechanical advantage is unit-less (has no unit) since it is a ratio between two forces.

Hope this helps :)
3 0
3 years ago
A stone is thrown upward at an angle. what happens to the horizontal component of its velocity as it rises? as it falls?
Ne4ueva [31]
<span>Rising or falling, it does not change.</span>
5 0
3 years ago
PLEASE HELP ME WHATS THE ASNWRR
stealth61 [152]

Answer:

think its b i dunno

Explanation:

7 0
2 years ago
Read 2 more answers
At one instant, a 17.0-kg sled is moving over a horizontal surface of snow at 4.10 m/s. After 6.15 s has elapsed, the sled stops
jasenka [17]

Answer:

force = 11.33 kg-m/s^{2}

Explanation:

given data:

sled mass = 17.0 kg

inital velocity (U) = 4.10 m/s

elapsed time (T) 6.15 s

final velocity (V) = 0

final momentum P2 = 0

Initial momentum of sledge is

P_{1}=mU

P_{1}= 17.0 * 4.10 = 69.7 kg- m/s

from newton second law of motion

F=\frac{\Delta P}{\Delta t}

F = \frac{P_{1}-P_{2}}{T}

Kgm/s^2

F = \frac{69.7-0}{6.15}= 11.33[tex]kg-m/s^{2}[/tex]

8 0
3 years ago
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