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natulia [17]
3 years ago
14

A weightlifter lifts a 250-kg mass 0.5 meters above his head, how much PEg does the mass have (Note: g=9.8 m/s2)? Round your ans

wer to the nearest whole number.
Physics
2 answers:
Anna71 [15]3 years ago
6 0
The Gravitationa potential energy of the mass (PEG) is given by:
U=mgh
where
m is the mass
g is the gravitational acceleration
h is the heigth of the mass above the reference level (the ground)

In this problem, m=250 kg and h=0.5 m, therefore the gravitational potential energy of the mass is:
U=mgh=(250 kg)(9.8 m/s^2)(0.5 m)=1225 J
emmainna [20.7K]3 years ago
3 0

Answer:

i can confirm it is 1,225

Explanation:

based on the website. I just did this question.

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An object with a mass of 1500kg accelerates 10.0m/s when unknown force is applied to it. What is the amount of force?
Hatshy [7]

Answer:

<h3>The answer is 15000 N</h3>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 1500 × 10

We have the final answer as

<h3>15,000 N</h3>

Hope this helps you

5 0
3 years ago
Read 2 more answers
What are three properties of electromagnetic waves?
Zolol [24]

The three properties of electromagnetic waves are; they travel at the speed of light, they include ultraviolet waves, and they can transfer energy through empty space.

<h2>Further Explanation</h2><h3>A wave</h3>
  • A wave is a transmission of a disturbance. It involves transmission of energy from one point which is the source to another point.
  • Waves may be classified depending on the need for a transmission medium or based on the vibration of particles relative to the direction of wave motion.
  • Waves may be either transverse or longitudinal based on the direction of wave motion relative to the vibration of particles
  • Additionally waves may be classified as either electromagnetic wave or mechanical based on the need for a transmission medium.
<h3>Electromagnetic waves  </h3>
  • Electromagnetic waves are types of waves that do not require a material medium for transmission.
  • All waves of the electromagnetic spectrum are electromagnetic transverse waves that do not require a material medium for transmission.
  • They include; radio waves, microwaves, infrared, visible light, ultra-violet, x-rays, and gamma rays.
  • All waves of the electromagnetic spectrum travel with a speed of light, 3.0 x10^8 m/s.
  • Additionally, electromagnetic waves possess energy that is given by; E = hf; where h is the plank's constant and f is the frequency.

keywords: Wave, electromagnetic wave, electromagnetic spectrum

<h2>Learn more about: </h2>
  • Waves: brainly.com/question/5354733
  • Electromagnetic waves: brainly.com/question/5354733
  • Electromagnetic spectrum: brainly.com/question/5354733
  • Velocity, speed and wavelength: brainly.com/question/11898955

Level: High school

Subject: Physics

Topic: Electromagnetic spectrum

Sub-topic: Properties of an electromagnetic waves

5 0
3 years ago
Read 2 more answers
An object ends up at a final position of x=-55.25 meters after a displacement of -189.34 meters after a displacement of -189.34
Travka [436]

The initial position of the object was found to be 134.09 m.

<u>Explanation:</u>

As displacement is the measure of difference between the final and initial points. In other words, we can say that displacement can be termed as the change in the position of the object irrespective of the path followed by the object to change the path. So

Displacement = Final position - Initial position.

As the final position is stated as -55.25 meters and the displacement is also stated as -189.34 meters. So the initial position will be

Initial position of the object = Final position-Displacement

Initial position = -55.25 m - (-189.34 m) = -55.25 m + 189.34 m = 134.09 m.

Thus, the initial position for the object having a displacement of -189.34 m is determined as 134.09 m.

4 0
3 years ago
An electron has an initial velocity of (19.0 j + 18.0 k) km/s and a constant acceleration of (3.00 ✕ 1012 m/s2)i in a region in
asambeis [7]

Answer:

E=(-17.08 i +7.2 j -7.6 k )N/C

Explanation:

v= (19.0j+18.k)km/s

a=3.0x10^{13}m/s^2

\beta= 400x10{-6}T

Electron information needed to solve the question:

m_e=9.11x10^{-31}kg

q=-1.6x10{-19}C

F=F_E+F_B=q*(E+Vx \beta)

F=m*a

m*a=q*(E+Vx\beta)

E=\frac{m*a}{q}-(Vx\beta )

E=\frac{9.11x10{-31}kg*3.0x10^{12}m/s^2}{-1.6x10{-19}C}-[(19.0x10^3mj+18.0x10^3m)xi(400x10^{-6}T)]

E=-i17.08N/C-[7.6(-k)+7.2(j)]N/C

E=(-17.08 i +7.2 j -7.6 k )N/C

6 0
3 years ago
Physics Help Please!!!
liq [111]
The answer is the third graph
3 0
3 years ago
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