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grandymaker [24]
3 years ago
7

How many solute particles are found inside the cell

Chemistry
1 answer:
vazorg [7]3 years ago
7 0

it should either be 5 or 10


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What are the limitations of Bronsted-Lowery concept???
HACTEHA [7]

Answer:

There is no limitation at all because that is the basic theory of solution electrolysis

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4 years ago
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Why is there not a corresponding drop in ionization energies between Bi and Po in the sixth period as N and O?
Stels [109]

Answer:

See explanation

Explanation:

According to the Journal of Chemical Education, Volume 80, No.8 (2003); "The first ionization energy of bismuth appears to be  anomalous......It has been claimed that spin– orbit coupling by the Russell–Saunders scheme would lower  the ground state of Bi+ ..."

However, the involvement of  d and f orbitals in Bi and Po implies that the outermost orbitals are poorly screened hence the drop between nitrogen and oxygen is not observed between Bi and Po.

The same argument could be extended to explain the reason why  there not a corresponding drop between Ba and Tl is the sixth period even though they are in the same group as Be and B.

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3 years ago
The Hertz (Hz) is the unit of measure for which wave property?
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3 years ago
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The metal content of iron in ores can be determined by a redox procedure in which the sample is first oxidized with Br2 to conve
coldgirl [10]

Answer:

80.27%

Explanation:

Let's consider the following balanced equation.

2 Fe³⁺(aq) + Sn²⁺(aq) ⇒ 2Fe²⁺(aq) + Sn⁴⁺(aq)

First, we have to calculate the moles of Sn²⁺ that react.

\frac{0.1015molSn^{2+} }{1L} .13.28 \times 10^{-3} L=1.348\times 10^{-3}molSn^{2+}

We also know the following relations:

  • According to the balanced equation, 1 mole of Sn²⁺ reacts with 2 moles of Fe³⁺.
  • 1 mole of Fe³⁺ is oxidized from 1 mole of Fe.
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Then, for 1.348 × 10⁻3 moles of Sn²⁺:

1.348\times 10^{-3}molSn^{2+}.\frac{2molFe^{3+} }{1molSn^{2+} } .\frac{1molFe}{1molFe^{3+} } .\frac{55.84gFe}{1molFe} =0.1505gFe

If there are 0.1505 g of Fe in a 0.1875 g sample, the mass percentage of Fe is:

\frac{0.1505g}{0.1875g} \times 100 \% = 80.27\%

5 0
3 years ago
6. What is the wavelength (in meters) of the electromagnetic carrier wave transmitted by The Sports
Vsevolod [243]

Answer:

wavelength = 2.81 m

Explanation:

Given that,

The frequency of the Sports  Fan radio station, f = 106.4 MHz

We need to find the wavelength (in meters) of the electromagnetic carrier wave. The relation between frequency and wavelength is given by :

c=f\lambda

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\lambda is wavelength

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So, the wavelength of the electromagnetic carrier wave is 2.81 m.

8 0
3 years ago
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