Question

If water (p=998 kg/m3, u = 10-3 Pa.s) flows through a 50 m Pa.s) determine the velocity of carbon tetrac me the velocity of carbon tetrachloride (p = 1590 kg/m", u = 0.958 x 10 howing through a 60 mm-diameter pipe so that they both have the same dynamic characteristics (Reynolds number similarity, Re = puD/).

Answer 1

Explanation:

As it is given that both have same dynamic characteristics.

Therefore,      $Re_{water}$ = $Re_{CCl_{4}}$

    $\frac{\rho_{water} \times \nu_{water} \times D_{water}}{\mu_{water}}$ =  $\frac{\rho_{CCl_{4}} \times \nu_{CCl_{4}} \times D_{CCl_{4}}}{\mu_{CCl_{4}}}$

Hence, putting the given values into the above formula as follows.

   $\frac{998 kg/m^{3} \times 2 m/s \times 50 mm}{10^{-3}Pa.s}$ =  $\frac{1590 kg/m^{3}} \times \nu_{CCl_{4}} \times 60 mm}{0.958 \times 10^{-3}}$    

                   $\nu_{CCl_{4}}$ = 1.002 m/s

Thus, we can conclude that the velocity of carbon tetrachloride in the given conditions is 1.002 m/s.