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GalinKa [24]
3 years ago
15

A man swims at a speed of 0.4 m/s. How long will it take him to cross a pool of length 50 m?

Physics
1 answer:
konstantin123 [22]3 years ago
7 0
Distance = speed * time, then time = distance / speed.

time = 50 / 0.4 = 125 s
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A ground state hydrogen atom absorbs a photon of wavelength 94.98 nm and its electron attains a higher energy level. The atom th
BaLLatris [955]

Answer: 102.63 nm

Explanation: In order to explain this problem we have to considerer the Plack postulate for the energy of the photons given by:

E=h*c/λ where H and c are the Planck constant and speed of light.

E=1240 nm*eV/94.98 nm= 13.05 eV

Then we have a first emitted photon with a wavelength of 1282.2 nm so  its energy is;

Einter=1240/1282.2=0.97 eV

so the energy to get the ground state from this level is

E=(13.05-0.97)=12.08 eV

From this level, the second  emitted photon has a wavelength given by:

λ=1240/12.08=102.65 nm

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3 years ago
In your own words, describe why melting ice with salt freezes cream. Compare your descriptions to your classmates and describe h
gizmo_the_mogwai [7]

Answer:

Water normally freezes at 0°C (32°F). Salt lowers the freezing temperature. (That is, it can remain a liquid at much lower temperatures.)

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When making ice cream, the salt lowers the temperature of the ice and water sufficiently enough to freeze the cream.

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Why are collisions between galaxies more likely than collisions between stars within a galaxy?
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Answer:

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8 0
3 years ago
When the dog shakes his body, his fur and the droplets of water clinging to it move in circular arcs. If the droplets leave the
AysviL [449]

Answer:

A) True. The droplets will move in parabolic arcs.

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Pair to describe a central force that changes its speed, but this force does not exist once they leave the dog

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4 0
4 years ago
Help me please I need to turn it in before midnight...
ale4655 [162]

Answer:

The statement which explains how the total time spent in the air is affected as the projectile's angle of launch increases from 25 degrees to 50 degrees is;

C. Increasing the angle from 25° to 50° will increase the total time spent in the air

Explanation:

The equation that can be used to find the total time, T, spent in the air of a projectile is given as follows;

T = \dfrac{2 \cdot u \cdot sin(\theta) }{g}

Where;

T = The time of flight of the projectile = The time spent in the air

u = The initial velocity of the projectile

θ = The angle of launch of the projectile

g = The acceleration due to gravity ≈ 9.81 m/s²

Given that sin(50°) > sin(25°), when the angle of launch, θ, is increased from 25 degrees to 50 degrees, we have;

Let T₁ represent the time spent in the air when the angle of launch is 25°, and let T₂ represent the time spent in the air when the angle of launch is 50°, we have;

T_1 = \dfrac{2 \cdot u \cdot sin(25^{\circ}) }{g}

T_2 = \dfrac{2 \cdot u \cdot sin(50^{\circ}) }{g}

sin(50°) > sin(25°), therefore, we have;

\dfrac{2 \cdot u \cdot sin(50^{\circ}) }{g} >   \dfrac{2 \cdot u \cdot sin(25^{\circ}) }{g}

Therefore;

T₂ > T₁

Therefore, increasing the angle at which the projectile is launched from 25° to 50° will increase the total time spent in the air.

7 0
3 years ago
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