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vaieri [72.5K]
3 years ago
13

HELP ASAP PLEASE!!! A car starting from rest, accelerates constantly at 8m/s2 for 6s. How far did it travel during this time per

iod?
Physics
2 answers:
insens350 [35]3 years ago
7 0

Answer:

Explanation:

initial velocity(u) = 0 since it is starting from rest

acceleration(a) = 8m/s^2

time(t) = 6s

distance(s) = ?

s = ut + 1/2 at^2

s = 0 × 6 + 1/2 × 8 × (6)^2

s = 0 + 1/2 × 8 × 36

s = 0 + 144

s = 144 m

hope this helps

plz mark it as brainliest!!!!!!

nikdorinn [45]3 years ago
4 0
Using the equation a= d/t
Where a is acceleration, d is distance and t is time.
The answer is 48m

Explanation
A=d/t
8=?/6
You times both sides by 6
And get
8x6=?
And thus the answer is 48
And when u put in the units it’s
48 meters

Hope this helps !!
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Make sure your response is 3-5 sentences.
g100num [7]

Answer: please see below

Explanation:

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Because of theses extreme conditions that pose challenges to space explorations, necessary precautions should be taken into consideration to be able to overcome such challenges. These precautions include building the spacecraft and the control unit in such a way that can resist these harmful conditions, also taking in mind safe escape routes for the astronauts in case of failures.

8 0
3 years ago
After a nucleus undergoes radioactive decay, its new mass number is:
Ivanshal [37]
Radioactive "decay" means particles and stuff shoot OUT of a nucleus.
After that happens, there's less stuff in the nucleus than there was before.
So the new mass number is always less than the original mass number.
7 0
4 years ago
Read 2 more answers
Which star has the highest surface temperature?
lesya [120]

Answer:

white star

Explanation:

because it is the hottest form of a star

7 0
3 years ago
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Two identical projectiles were projected at 200 km/h the first one is at an angle 60 to the horizontal while the second one is a
Setler79 [48]

Answer:

The angle that will have the most range (Goes further) <u>will be the one that is shot with 60 ° with the horizontal. </u>

Since the one that shoots with respect to the vertical, it will only reach higher. And it won't go as far as the horizontal.

Greetings.

Danna.

3 0
3 years ago
You are climbing in the high sierra when you suddenly find yourself at the edge of a fog-shrouded cliff. to find the height of t
sergey [27]
The total time it takes the sound to reach our on top of the cliff (10.0 s) is actually sum of two times:
- the time it takes the rock to hit the ground starting from the top of the cliff, t1
- the time it takes the sound to reach the top of the cliff starting from the ground, t2
1) The rock moves by uniformly accelerated motion, with constant acceleration g=9.81 m/s^2. Its law of motion is given by y(t)=h-v_0t-\frac{1}{2}gt^2, where v_0=0 is the initial velocity of the rock, and h is the height of the cliff. The time t1 is the time at which the rock reaches the ground, so that y(t1)=0, and the equation becomes
0=h-\frac{1}{2}gt_1^2
2) The sound moves from the ground to the top of the cliff by uniform motion, with constant speed v=343 m/s. Therefore, the sound covers the distance h (the height of the cliff) in a time t2 given by
h=vt_2
3) If we rewrite h in both equations, we can write:
=\frac{1}{2}gt_1^2=vt_2 (1)
4) We also know that the sum of t1 and t2 is equal to 10 seconds:
t_1+t_2=10
from which we find
t_2=10-t_1
if we substitute this into eq.(1), we get
\frac{1}{2}gt_1^2+vt_1-10v=0
Numerically:
4.9t_1^2 + 343 t_1 - 3430=0
Solving the equation, we find the solution t_1=8.87 s (the other solution is negative, so it does not have physical meaning). As a consequence,
t_2 = 10-t_1 = 1.13 s
and the height of the cliff is given by
<span>h=vt_2=(343 m/s)(1.13 s)=388 m</span>
3 0
3 years ago
Read 2 more answers
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