(a)
KE = m v^2 / 2 = (1200 kg)(20 m/s)^2 / 2 = 240,000 J
(b)
The energy is entirely dissipated by the force of friction in the brake system.
(c)
W = delta KE = KEf - KEi = (0 - 240,000) J = -240,000 J
(d)
Fd = delta KE
F = (delta KE) / d = (-240,000 J) / (50 m) = -4800 N
The magnitude of the friction force is 4800 N.
Answer:
Cosmic ray is not considered electromagnetic radiation.
Explanation:
Electromagnetic radiation refers to
- It is Radiation that has both electric and magnetic fields and travels in waves.
- Electromagnetic radiation can vary in strength from low energy to high energy.
X rays are the rays produced when a negatively charged electrode is heated by electricity and electrons are released, thereby producing energy. It is a type of radiation called EM waves.
Radio wave are wave from the portion of the electromagnetic spectrum at lower frequencies than microwaves. It is an EM wave.
Ultraviolet wave Invisible rays that are part of the energy that comes from the sun. It is an example of EM wave.
Cosmic ray is a high-speed particle either an atomic nucleus or an electron that travels through space.
Cosmic ray is not an electromagnetic wave.
Hence
Cosmic ray is not considered electromagnetic radiation
learn more about electromagnetic radiation here:
<u>brainly.com/question/13695751</u>
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To solve this problem it is necessary to apply the concepts related to Kinetic Energy, specifically, since it is a body with angular movement, the kinetic rotational energy. Recall that kinetic energy is defined as the work necessary to accelerate a body of a given mass from rest to the indicated speed.
Mathematically it can be expressed as,
Where
I = Moment of Inertia
Angular velocity
Our values are given as
A revolution is made every 4.4 seconds.
If the angular velocity is equivalent to the displacement over the time it takes to perform it then
Replacing at our previous equation we have,
Therefore the kinetic energy is equal to 
