When the position of the mass is farthest from the equilibrium position, what is the velocity of the mass?
1 answer:
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Answer:
15m/s²
Explanation:
Given parameters:
Initial velocity = 10m/s
Final velocity = 40m/s
Time taken = 2s
Unknown:
Average acceleration = ?
Solution:
Acceleration is the rate of change of velocity with time;
Acceleration =
Acceleration = = 15m/s²
Answer:
23. 4375 m
Explanation:
There are two parts of the rocket's motion
1 ) accelerating (assume it goes upto h1 height )
using motion equations upwards
Lets find the velocity after 2.5 seconds (V1)
V = U +at
V1 = 0 +5*2.5 = 12.5 m/s
2) motion under gravity (assume it goes upto h2 height )
now there no acceleration from the rocket. it is now subjected to the gravity
using motion equations upwards (assuming g= 10m/s² downwards)
V²= U² +2as
0 = 12.5²+2*(-10)*h2
h2 = 7.8125 m
maximum height = h1 + h2
= 15.625 + 7.8125
= 23. 4375 m