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3 years ago

Bena thinks that dissolving more salt in water causes the mixture’s freezing temperature to change.

Physics

2 answers:

ValentinkaMS [17]3 years ago

4 0

Answer:

ok im not 100% sure but i think it would be A or C

Explanation:

i am so sorry if im wrong :(

IRISSAK [1]3 years ago

3 0

Entropy and the second Law of Thermodynamics

Dissolving salt into water lowers the temperature which the water freezes, or at which the ice melts

Hope I helped! (:

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Bill is farsighted and has a near point located 119 cm from his eyes. Anne is also farsighted, but her near point is 70.0 cm fro

Gennadij [26K]

Answer:

Explanation:

For Bill's glasses)

d_o=25 cm-2 cm=23.2 cm

d_i=129 cm-2 cm=127 cm

We know that

$1 / f = 1 / d_o + 1 / d_i
$

$f=(1 / d_o + 1 / d_i)^-1
$

so plug the numbers in

$f = (1 / (23) + 1 / (127))^-1
$

= 28.08 cm

For Anna's glasses)

d_o=25 cm-2 cm=23 cm

d_i=70.0 cm-2 cm=68 cm

Same thing

$(1 / f = 1 / d_o + 1 / d_i
)$

$f=(1 / do + 1 / di)^-1
$

so plug the numbers in

$f = (1 / (23) + 1 / (68))^-1
$

= 17.21 cm

5 0

3 years ago

Heat is most closely related to____ energy.

OLEGan [10]

Heat is most closely related to THERMAL energy.

4 0

3 years ago

Read 2 more answers

Brandon buys a new Seadoo He goes 12 km north from the beach . He jumps wakes for 6 km to the east . What distance cover ? What

zmey [24]

Answer:

distance- I think it is 6 then the displacement is 13.41

Explanation:

4 0

3 years ago

6. What is the change in temperature of a metal rod that is 55.0 cm long, decreases length by 0.20 cm, and that has a coefficien

MrMuchimi

Explanation:

We have,

Length of a metal rod is 55 cm or 0.55 m

Change in length is 0.2 cm or 0.002 m

It is required to find the change in temperature of a metal rod. The coefficient of linear expansion is given by :

$\alpha =\dfrac{\Delta L}{L_0\Delta T}$

$\Delta T$ is the change in temperature

$\Delta T =\dfrac{\Delta L}{L_0\alpha }\\\\\Delta T =\dfrac{0.002}{0.55\times 12\times 10^{-6}}\\\\\Delta T= 303.03^{\circ} C$

So, the change in temperature is 303.03 degrees Celsius.

4 0

3 years ago

In a model AC generator, a 505 turn rectangular coil 8.0 cm by 30 cm rotates at 120 rev/min in a uniform magnetic field of 0.59

Ludmilka [50]

(a) Maximum emf: 90 V (2 sig. fig.)
(b) Emf at π/32 s: 85 V.
(c) t = 0.125 s.

<h3>Explanation</h3><h3>(a)</h3>

The maximum emf in the coil depends on

the maximum flux linkage through the coil, and
the angular velocity of the coil.

Maximum flux linkage in the coil:

$\phi_\text{max} = B\cdot A\cdot N = 0.59\;\text{T}\times(0.08 \times 0.30)\;\text{m}^{2} \times 505 = 7.2\;\text{Wb}$ .

Frequency of the rotation:

$f = 120\;\text{rev}\cdot\text{min}^{-1} = 2 \;\text{rev}\cdot\text{s}^{-1}$ .

Angular velocity of the coil:

$\omega = 2\;\pi\;\text{rev}^{-1}\times 2\;\text{rev}\cdot\text{s}^{-1} = 4 \pi \;\text{s}^{-1}$ .

Maximum emf in the coil:

$\epsilon_\text{max} = \omega\cdot\phi_\text{max} = 4\;\pi \times 7.2\;\text{Wb} = 90\;\text{V}$ .

Emf varies over time. The trend of change in emf over time resembles the shape of either a sine wave or a cosine wave since the coil rotates at a constant angular speed. The question states that emf is "zero at t = 0." As a result, a sine wave will be the most appropriate here since $\sin{0} = 0$ .

$\displaystyle \epsilon(t) = \epsilon_\text{max}\cdot \sin{(\omega\cdot t)}$ .

Make sure that your calculator is in the radian mode.

$\displaystyle \epsilon\left(\frac{\pi}{32}\right) = 90\;\text{V}\times \sin\left(4\;\pi\times \frac{\pi}{32}\right) = 85\;\text{V}$ .

Consider the shape of a sine wave. The value of $\displaystyle \sin\left(\omega \cdot t\right)$ varies between -1 and 1 as the value of $t$ changes. The value of $\epsilon$ at time $t$ depends on the value of $\sin(\omega \cdot t)$ .