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enot [183]
3 years ago
5

How do two electrons in the same orbital compare in terms of the spin quantum number (ms)?

Chemistry
1 answer:
DIA [1.3K]3 years ago
3 0
If there are 2 electrons in the same orbital, the spin numbers would be different for both of these 2 electrons. One would have an up spin and the other a down spin.
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Please help I will mark Brainly!
olga nikolaevna [1]
I think C. Ionic compounds are very difficult to break apart because they are fully negative or positive charges, like magnets.
8 0
3 years ago
If two gases, A and B, in separate 1 liter containers exert
babunello [35]

Answer:

5Atm

Explanation:

I just guess and it’s right

5 0
3 years ago
What are all the intermolecular forces present in a sample of BrF?
yuradex [85]

Answer:

dipole-dipole

Explanation:

Intermolecular forces exists between the molecules of a substance in a particular state of matter.

The type of intermolecular forces present in  a substance is determined by the electronegativity difference between the atoms that compose the substance.

There is a non zero electronegativity difference  between Br and F hence the molecule is polar and the intermolecular forces between the molecules of BrF are dipole-dipole forces.

4 0
3 years ago
Jessica has 12.7 moles of a compound for an experiment. How many particles of the compound does she have?
guajiro [1.7K]

Answer:

Number of moles is defined as the ratio of given mass in g to the molar mass.The mathematical expression is given as:

Number of moles  =Number of moles of compound  = 12.7 moles (given)As, 1 mole of any compound is equal to  particles.

where,    is Avogadro number. Formula for calculating particles is given by:

where, N =  number of particles, n = number of moles and  is Avogadro number.

Put the values,=  or  Hence, number of particles of the compound is equal to

Explanation:

8 0
3 years ago
Read 2 more answers
PLEASE HELP QUICK AS POSSIBLE!!!!
GalinKa [24]

Answer:

4180J

Explanation:

(25.0g)(4.184J/g°C)(75°C-35.0°C)

(25.0g)(40.0°C)(4.184J/g°C)

(1.00*10³g°C)(4.184J/g°C) = 4184J

use sig figs:

4180J

8 0
3 years ago
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