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Svet_ta [14]
2 years ago
11

A grindstone increases in angular speed from 4.00 rad/s to 12.00rad/s in 4.00 s. Through what angle does it turn during that tim

e interval if the angular acceleration is constant? (a) 8.00rad (b) 12.0rad (c) 16.0rad (d) 32.0rad (e) 64.0rad
Physics
1 answer:
Talja [164]2 years ago
3 0

Through what angle does it turn during that time interval if the angular acceleration is constant: 32.0rad.

<h3>What is angular acceleration?</h3>
  • Angular acceleration is the term used to describe the temporal pace at which angular velocity varies. Radians per second is the accepted unit of measurement. Consequently, = d d t. Angular acceleration is also known as rotational acceleration.

  • Angular acceleration can be calculated by dividing the angular velocity by the acceleration duration. (t). Use pi instead, or the drive speed (n) divided by the acceleration time (t) multiplied by 30. The usual SI unit for the rotational acceleration that results from this equation is radians per second squared (Rad/sec2).

Through what angle does it turn during that time interval if the angular acceleration is constant:

v(initial) = 4rad/s

v(final) = 12

t = 4 sec

a = ?

v(final) = v(initial) + at

12 = 4 + a(4)

a = 2 rad/sec2

s = ?

v(initial) = 4rad/s

v(final) = 12

a = 2rad/sec2

v(final)^2 = v(initial)^2 + 2as

12^2 = 4^2 + 2(2)(s)

144 = 16 + 4s

s = 32 rads

d) 32.0rad.

To learn more about angular acceleration, refer to:

brainly.com/question/20912191

#SPJ4

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A single insulated duct flow experiment using air operating at steady-state is performed in a lab. One measurement location (Sta
weqwewe [10]

Answer:

a) -0.0934 kJ/kg. K

b) The direction of flow is from right to left.

Explanation:

A free flow diagram of the horizontal insulated duct is as shown below.

NOW,

Let assume that the direction of flow is from left to right and consider the following relation for the entropy rate balance equation for a control volume as:

\frac{\sigma_{cv}}{m}= (s_2-s_1) \geq  0 \ \ \ -------> \ \ \ 1

Now; if the value for this relation is greater than zero; then we conclude that our assumption is correct.

If the value is less than zero; then we conclude that the assumption is wrong.

Then, the flow is said to be  in the opposite direction

Formula for the change in specific entropy can be calculated as:

s_2-s_1 = s^0(T_2) - s^0(T_1)-R \ In ( \frac{P_2}{P-1}) \ \ \  ------->  \ \ \ 2

where;

s_1, s_2 , s^0(T_2), s^0(T1) are specific entropies

R = universal gas constant

P_1 = pressure at location 1

P_2 = pressure at location 2

We obtain the specific properties of air at temperature at T_1 = (67°C + 273)K = 340 K from the table A-22 ( Ideal gas properties of air)

s^0(T1) = 1.8279 kJ/kg.K

We also obtain the specific properties of air at temperature T_2 = 22°C + 273) K = 295 K

From the table A- 22

s^0(T_2) = 1.68515 kJ/kg . K

R = \frac{8.314 kJ}{28.97 kg.K}

P_1 = 0.95 bar

P_2 = 0.8 bar

Now replacing our values  into equation (2) from above; we have;

s_2-s_1 = s^0(T_2) -s^0(T_1)-R \ In (\frac{P_2}{P_1} )

s_2-s_1 = 1.68515 -1.8279-\frac{8.314}{28.97}  \ In (\frac{0.8}{0.95} )

s_2-s_1 = 1.68515 -1.8279+ 0.0493

s_2-s_1 =-0.0934 \  kJ/kg.K

Equating our result to equation (1)

s_2-s_1 \geq 0\\-0.0934 \leq 0

Therefore , our assumption is wrong and the direction of flow is said to be from right to left.

We therefore conclude that the direction of flow is from right to left.

3 0
4 years ago
Help ASAP.
Temka [501]

Answer:

Depending on where people are located in the world (Northern hemisphere, Southern hemisphere, etc) depends on the difference in direction (North, South, east, West) which is most likely why it'd look different.

Explanation:

I dunno if this is along the lines of an answer you're looking for, but hope this helps :)

7 0
3 years ago
You push a table 8 meters for 16 minuutes and do 6720 j of work how much power do ypu use
Yuri [45]
P=W/t

P=Power
W=Work
t=Time

Convert 16 minutes in seconds:
16 mins = 960 secs

P=6720/960=7.23 W [Watt]
3 0
3 years ago
A bottle lying on the windowsill falls off and takes 4.95 seconds to reach the ground. The distance from the windowsill to the g
Liula [17]
The distance an object falls from rest through gravity is 
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           Distance  =  (1/2 acceleration of gravity) x (square of the falling time)

We want to see how the time will be affected 
if  ' D ' doesn't change but ' g ' does. 
So I'm going to start by rearranging the equation
to solve for ' t '.                                                      D  =  (1/2) (g) (t²)

Multiply each side by  2 :         2 D  =            g    t²  

Divide each side by ' g ' :      2 D/g =                  t² 

Square root each side:        t = √ (2D/g)

Looking at the equation now, we can see what happens to ' t ' when only ' g ' changes:

  -- ' g ' is in the denominator; so bigger 'g' ==> shorter 't'

                                             and smaller 'g' ==> longer 't' .-- 

They don't change by the same factor, because  1/g  is inside the square root.  So 't' changes the same amount as  √1/g  does.

Gravity on the surface of the moon is roughly  1/6  the value of gravity on the surface of the Earth.

So we expect ' t ' to increase by  √6  =  2.45 times.

It would take the same bottle  (2.45 x 4.95) = 12.12 seconds to roll off the same window sill and fall 120 meters down to the surface of the Moon.
5 0
3 years ago
Fusion and fission are both processes that involve which fundamental force? to ask? A. gravitational B. weak nuclear C. electrom
marin [14]
Fusion & Fission are both processes that involve D. Strong Nuclear Fundamental forces
"D". is the answer
5 0
4 years ago
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