let us consider that the two charges are of opposite nature .hence they will constitute a dipole .the separation distance is given as d and magnitude of each charges is q.
the mathematical formula for potential is 
for positive charges the potential is positive and is negative for negative charges.
the formula for electric field is given as-
for positive charges,the line filed is away from it and for negative charges the filed is towards it.
we know that on equitorial line the potential is zero.hence all the points situated on the line passing through centre of the dipole and perpendicular to the dipole length is zero.
here the net electric field due to the dipole can not be zero between the two charges,but we can find the points situated on the axial line but outside of charges where the electric field is zero.
now let the two charges of same nature.let these are positively charged.
here we can not find a point between two charges and on the line joining two charges where the potential is zero.
but at the mid point of the line joining two charges the filed is zero.
A proton in a particle accelerator is traveling at a speed of 0.99c has a speed magnitude of 2.97 x 10⁸ m/s.
<h3>What is speed of proton?</h3>
The speed of a proton is the rate at which a proton is moving through a given space.
The given speed of the proton is 0.99c
where;
<h3>What is speed of light?</h3>
The speed of light in vacuum, commonly denoted c, is a universal physical constant that is important in many areas of physics.
The value of speed of light in a vacuum is given as 3 x 10⁸ m/s.
The speed of the proton is calculated as follows;
v = 0.99 x 3 x 10⁸ m/s.
v = 2.97 x 10⁸ m/s.
Thus, a proton in a particle accelerator is traveling at a speed of 0.99c has a speed magnitude of 2.97 x 10⁸ m/s.
Learn more about speed of proton here: brainly.com/question/14663642
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Answer: A Neutron.
I know this is correct. Thank's and yw :3