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3 years ago

How to change V=72km/hr to m/s

1 answer:

7 0

Multiply by (1000 meters / 1 km).
Then multiply by (1 hour / 3600 seconds).

Both of those fractions are equal to ' 1 ', because the top
and bottom numbers are equal, so the multiplications
won't change the VALUE of the 72 km/hr. They'll only
change the units.

(72 km/hour) · (1000 meters / 1 km) · (1 hour / 3600 seconds)

= (72 · 1000 / 3600) (km·meter·hour / hour·km·second)

= 20 meter/second

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Please help answer question

nika2105 [10]

Answer:

C = 1.01

Explanation:

Given that,

Mass, m = 75 kg

The terminal velocity of the mass, $v_t=60\ m/s$

Area of cross section, $A=0.33\ m^2$

We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,

R = W

$\dfrac{1}{2}\rho CAv_t^2=mg$

Where

$\rho$ is the density of air = 1.225 kg/m³

C is drag coefficient

So,

$C=\dfrac{2mg}{\rho Av_t^2}\\\\C=\dfrac{2\times 75\times 9.8}{1.225\times 0.33\times (60)^2}\\\\C=1.01$

So, the drag coefficient is 1.01.

4 0

2 years ago

Wave C has an amplitude of 1 and wave D has an amplitude of 3 as shown below. What will happen when the trough of wave C meets t

gtnhenbr [62]

They will interfere to create a crest with an amplitude of 2

4 0

3 years ago

Read 2 more answers

The volume of gas in a flexible container at a depth of 10 m/33 ft will expand to ______ its original volume if taken to the sur

natulia [17]

The volume of gas in a flexible container at a depth of 10 m/33 ft will expand to double its original volume if taken to the surface.

What is volume:

The amount of space that a substance or object occupies.

Volume is denoted with letter V

What is a gas molecule?

Generally, a gas molecule is simply defined as a combination of numbers of atoms that are connected one to another.

here, 10 m/33 feet of sea water is taken to exerts a gauge pressure that is the same pressure as the atmosphere.

This means that we add one atmosphere/bar pressure for every 10 m/33 feet you descend.

The effect of this is that,

at 10 m/33 ft absolute pressure is two ata/bar

Adding another 10 m/33 ft to this depth to make it 20 m/66 ft, puts you under under three ata/bar of pressure and so on.

Descending to a depth it means that you have double the ata/bar pressure acting on you. If you decide to resurface, the pressure on the flexible container will reduce by a factor of two.

Since volume is inversely proportional to the pressure,

If the pressure reduces by a factor of 2, then the volume will increase by a factor of two.

Learn more about volume of gas here:

<u>brainly.com/question/17328636</u>

#SPJ4

3 0

1 year ago

Acceleration is always act in the direction of

hjlf

Answer:

Acceleration acts always in the direction. Of the displacement. Of the initial velocity.

5 0

2 years ago

An airplane has an effective wing surface area of 19.4 m2 that is generating the lift force. In level flight the air speed over

alexgriva [62]

Answer:

W =23807.68 N

Explanation:

given,

surface area of wing = 19.4 m²

speed over top wing = 67 m/s

speed under wing = 51 m/s

density of air = 1.3 kg/m³

weight of plane

From Bernoulli's principle

$P_1 + \dfrac{1}{2}\rho v_1^2 = P_2 + \dfrac{1}{2}\rho_2^2$

where 1 and 2 are two different locations at the same geo potential level

so if we call 1 the lower surface and 2 the upper surface,

we find the pressure differential, P₁ -P₂

$\Delta P =\dfrac{1}{2}\rho (v_2^2-v_1^2)$

$\Delta P =\dfrac{1}{2}\times 1.3 \times (67^2-51^2)$

$\Delta P =1227.2\ N/m^2$

then the force acting on the plane is

F=P A

F=1227.2 x 19.4

F =23807.68 N

weight of the plane

W =23807.68 N

7 0

3 years ago