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Oxana [17]
3 years ago
12

Perform the following unit conversions:

Chemistry
1 answer:
Y_Kistochka [10]3 years ago
4 0

Answer :

(a) The 60 feet of water is equal to 179344.2 Pa.

(b) The 220 psi is equal to 31680lbf/ft^2

(c) The 120 torr is equal to 15998.6 Pa.

(d) The 1.0 atm to inches of glycerin  is equal to 323.07 inches.

(e) The 1050 mm Hg is equal to 376.95lbf/ft^2

Explanation :

(a) The conversion used from feet to pascal is:

1\text{ feet}=2989.07Pa

As we are given that 60 feet of water. Now we have to convert into Pa.

As, 1\text{ feet}=2989.07Pa

So, 60\text{ feet}=\frac{60\text{ feet}}{1\text{ feet}}\times 2989.07Pa=179344.2Pa

The 60 feet of water is equal to 179344.2 Pa.

(b) The conversion used from psi to lbf/ft^2 is:

1\text{ psi}=144lbf/ft^2

As we are given that 220 psi. Now we have to convert into lbf/ft^2.

As, 1\text{ psi}=144lbf/ft^2

So, 220\text{ psi}=\frac{220\text{ psi}}{1\text{ psi}}\times 144lbf/ft^2=31680lbf/ft^2

The 220 psi is equal to 31680lbf/ft^2

(c) The conversion used from torr to pascal is:

1\text{ torr}=133.322Pa

As we are given that 120 torr. Now we have to convert into Pa.

As, 1\text{ torr}=133.322Pa

So, 120\text{ torr}=\frac{120\text{ torr}}{1\text{ torr}}\times 133.322Pa=15998.6Pa

The 120 torr is equal to 15998.6 Pa.

(d) 1.0 atm to inches of glycerin

Formula used : P=\rho gh

where,

P = pressure of glycerin = 1.0 atm = 101325 Pa

g = acceleration due to gravity = 9.8m/s^2

\rho = density of glycerin = 1260kg/m^3

Now put all the given values in above formula, we get:

101325Pa=(1260kg/m^3)\times (9.8m/s^2)\times h

h=8.206\frac{Pa.m^2s^2}{kg}=8.206m=323.07\text{ inches}

Conversion used :

1Pa=\frac{kg}{ms^2}\\\\1m=39.37inches

The 1.0 atm to inches of glycerin  is equal to 323.07 inches.

(e) The conversion used from psi to lbf/ft^2 is:

1\text{ mmHg}=0.359lbf/ft^2

As we are given that 1050 mmHg. Now we have to convert into lbf/ft^2.

As, 1\text{ mmHg}=0.359lbf/ft^2

So, 1050\text{ mmHg}=\frac{1050\text{ mmHg}}{1\text{ mmHg}}\times 0.359lbf/ft^2=376.95lbf/ft^2

The 1050 mm Hg is equal to 376.95lbf/ft^2

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Answer:

             0.324 g is required to make 5.00 M solution of NaCl in 0.800 L.

Given data:

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