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bezimeni [28]
2 years ago
8

Rohith has been jogging to the bus stop for 2.0 minutes at 3.5 m/s when he looks at

Physics
1 answer:
nikdorinn [45]2 years ago
6 0
Multiply these numbers and there’s your answer
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A 2kg ball is thrown with an acceleration of 15m/s2. A 2kg ball is thrown with an acceleration of 10m/s2. Which ball
DerKrebs [107]
A :-) for this question , we should apply
F = ma
( i ) Given - m = 2 kg
a = 15 m/s^2
Solution :
F = ma
F = 2 x 15
F = 30 N

( ii ) Given - m = 2 kg
a = 10 m/s^2
Solution :
F = ma
F = 2 x 10
F = 20 N

.:. The net force of object ( i ) has greater force compared to object ( ii ) by
( 30 - 20 ) 10 N

5 0
3 years ago
Mấy bạn việt nam giúp mình với. cần gấp quá
Basile [38]
Saying english so we can help u
6 0
2 years ago
As pressure decreases, temperature
Pani-rosa [81]
Temperature doesn't do anything, the boiling point of stuff decreases. If you put water in a vacuum chainber then it will start to boil
5 0
3 years ago
Please help me this is timed . <br> Find x if a = 3.0 m/s^2
storchak [24]

Answer:

x = 50 N

Explanation:

Given that we have a net force, a mass, and acceleration, we can use the fundamental formula for force found in newton's second law which is F = m × a.

Given a mass of 150 kg, and an acceleration 3.0m/s². We can substitute these two values in our formula to calculate the magnitude of these forces or it's net force to identify the unknown force acting on our known force for this situation to work.

_______

F (Net force) = F2 (Second force which we are given) - F1 (First force) = m × a

m (mass which we are given) = 150 kg

a (acceleration which we are given) = 3.0m/s

________

So F = m × a → F2 - F1 = m × a →

500 - F1 = 150 × 3.0 → 500 - F1 = 450 →

-F1 = -50 → F1 = 50

5 0
3 years ago
If a hockey stick exerts a force of 40 N on a 0.5-kg puck, what will the
antoniya [11.8K]

Answer:

  B.  80 m/s²

Explanation:

F = ma

a = F/m = (40 N)/(0.5 kg) = 80 m/s²

3 0
3 years ago
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