Answer:
height is the answer i'm pretty sure.
Explanation:
1 horsepower is equal to 746 W, so the power of the engine is
![P=47.4 hp \cdot 746 \frac{W}{hp}=35360 W](https://tex.z-dn.net/?f=P%3D47.4%20hp%20%5Ccdot%20746%20%20%5Cfrac%7BW%7D%7Bhp%7D%3D35360%20W%20)
The power is also defined as the energy E per unit of time t:
![P= \frac{E}{t}](https://tex.z-dn.net/?f=P%3D%20%5Cfrac%7BE%7D%7Bt%7D%20)
Where the energy corresponds to the work done by the engine, which is
![E=6.82 \cdot 10^5 J](https://tex.z-dn.net/?f=E%3D6.82%20%5Ccdot%2010%5E5%20J)
. Re-arranging the formula, we can calculate the time t needed to do this amount of work:
Answer:
B: Process #1: Energy is decreasing Process#2: Energy is increasing
Answer:
![3.2\cdot 10^{-8} N](https://tex.z-dn.net/?f=3.2%5Ccdot%2010%5E%7B-8%7D%20N)
Explanation:
The inital electrostatic force between the two spheres is given by:
![F=k\frac{q_1 q_2}{r^2}](https://tex.z-dn.net/?f=F%3Dk%5Cfrac%7Bq_1%20q_2%7D%7Br%5E2%7D)
where
is the initial force
k is the Coulomb's constant
q1 and q2 are the charges on the two spheres
r is the distance between the two spheres
The problem tells us that the two spheres are moved from a distance of r=20 cm to a distance of r'=10 cm. So we have
![r'=\frac{r}{2}](https://tex.z-dn.net/?f=r%27%3D%5Cfrac%7Br%7D%7B2%7D)
Therefore, the new electrostatic force will be
![F'=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(r/2)^2}=4k\frac{q_1 q_2}{r^2}=4F](https://tex.z-dn.net/?f=F%27%3Dk%5Cfrac%7Bq_1%20q_2%7D%7B%28r%27%29%5E2%7D%3Dk%5Cfrac%7Bq_1%20q_2%7D%7B%28r%2F2%29%5E2%7D%3D4k%5Cfrac%7Bq_1%20q_2%7D%7Br%5E2%7D%3D4F)
So the force has increased by a factor 4. By using
, we find
![F'=4(8\cdot 10^{-9} N)=3.2\cdot 10^{-8} N](https://tex.z-dn.net/?f=F%27%3D4%288%5Ccdot%2010%5E%7B-9%7D%20N%29%3D3.2%5Ccdot%2010%5E%7B-8%7D%20N)