Practically yes
So
If mass is more output may come less so it affects the efficiency practically
But thepritically it doesn't
Answer:
Use the form of equation:
Q=mL
You have the specific latent heat of vaporization L = 2.260*10^{6}
And Q, the heat energy supplied, which equals 1695 KJ = 1695*10^{3} J
So you can get the mass by substitution in the formula below.
I’m not sure I think it’s A
Answer:
100,800 Jkg
The heat that is used to change the state of a mater is called latent heat.
In this case it is converting ice to water and it is called latent heat of fusion.
It is given by:
Heat = mc
where m is the mass of ice and l is the specific latent heat of fusion of ice.
l = 0.336 MJ
Heat = 0.3 × 0.336 MJ
= 0.3 × 0.336 × 10⁶
= 100,800 Jkg