Question

A soccer ball is rolling with a constant acceleration of -1.5 m/s2 . At ti = 0 s, the ball has an instantaneous velocity of 14 m/s. After 3s of rolling, what would be the velocity of the ball (in m/s)?

Answer 1

Answer:

$v_{f} = 9.5\,\frac{m}{s}$

Explanation:

The final velocity is:

$v_{f} = v_{o} + a \cdot t$

$v_{f} = 14\,\frac{m}{s} + (-1.5\,\frac{m}{s^{2}} )\cdot (3\,s)$

$v_{f} = 9.5\,\frac{m}{s}$