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3 years ago

A concrete stepping-stone measures 20 square inches. What is the area of 30 such stones?

Mathematics

1 answer:

ozzi3 years ago

5 0

1 stone is 20 square inches

multiply that by 30 for total

20 *30 = 600 square inches total

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Solve the following systems algebraically a. x+2y=17 x-y=2

motikmotik

There are 3 methods to solve this. elimination substitution and graphing but i am going to use the elimination method.
x+2y=17
 x-y =2
 0+3y =15 ( subtracted down to eliminate the x)( x-x=0, 2y-(-y)=3y, and 17-2=15)
3y=15 (divide both sides by 3 to solve for y)
y=5
substitute the y=5 in any of the above equations and solve for x
ie... ( meaning where you find y in the equation, u replace it with a 5)

it will be easier to solve for x in (x-y=2) so i will use that one.
x-(5)=2 ( add 5 on both sides to solve for x)
x=7

5 0

3 years ago

PLEASE HELP!! URGENT

Slav-nsk [51]

1. The problem statement tells you to find "the area of the hexagonal face".

2. If we assume the intent is to find the shaded area of the face only, it differs from the area of a regular hexagon in that there is a hole in the middle.

3. You must find the area of the regular hexagon, and subtract the area of the circular hole in the middle.

4. The formula for the area of a circle in terms of its radius is

... A = πr²

5. The formula for the area of a regular hexagon in terms of the radius of the circumcircle is

... A = (3√3)/2·r²

6. The radius of the circumcircle of the regular hexagon is given. No additional information is needed.

7. You can use the trig functions of the angles of an equilateral triangle to find the apothem, but there is no need for that when you use the formula of 5.

8. All this is unnecessary. The apothem is (8 mm)·(√3)/2 = 4√3 mm ≈ 6.9282 mm, the shorter leg is (8 mm)·(1/2) = 4 mm. The perimeter is 6·8 mm = 48 mm.

9. The area of the hexagon is

... A = 3√3/2·(8 mm)² = 96√3 mm² ≈ 166.277 mm²

10. The area of the circle is

... A = π·(4 mm)² = 16π mm² ≈ 50.265 mm²

11. The area of the hexagonal face is approximately ...

... 166.277 mm² - 50.265 mm² = 116.01 mm²

6 0

3 years ago

Which sentence represents a relationship between the number of visits

Step2247 [10]

Choice (A) has zero slope becsuse her cost doesn't depend on the number of visits.

6 0

3 years ago

Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

I will try to give as many details as possible.

First of all, I just would like to say:

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Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! （＊＾Ｕ＾）人（≧Ｖ≦＊）/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

3 years ago

Please walk me through this

FinnZ [79.3K]

Answer:

X is 160. because you can add all the value of x. But first substrate 540 with 100 which is 440. then 1/2x + 1/2x+ (x-15) + (x-25) which is further simplified as x + 2x - 40. then it's further simplified as 3x - 40 = 440. then add 40 with 440 which is 480 then divide it by 3 which is 160. therefore X= 160.

3 0

3 years ago