Answer:
Covalent bond
Explanation:
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The amount of energy absorbed by the 325g of water is 57,057J. Details about calorimetry can be found below.
<h3>How to calculate energy?</h3>
The energy absorbed by a mass of substance can be calculated using the following formula;
Q = mc∆T
Where;
- Q = quantity of heat absorbed
- m = mass of substance
- c = specific heat capacity
- ∆T = change in temperature
Q = 325g × 4.18 × (92 - 50)
Q = 57,057J
Therefore, the amount of energy absorbed by the 325g of water is 57,057J.
Learn more about energy at: brainly.com/question/3609481
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<span>The answer is C. The volume decreases. A scuba diver at the surface of the sea takes a deep breath and fills her lungs with 6 liters of air. The pressure in her lungs is 1 atm. She then dives down ten meters, without inhaling or exhaling, until the pressure of the air in her lungs is 2 atm. According to Boyle’s law, the air in her lungs decreases as she dives down. </span>Boyle's Law<span> is the gas </span>law which states that in a closed space, pressure and volume are inversely related. As pressure increases, volume decreases, and vice versa.
Answer: The most likely partial pressures are 98.7MPa for NO₂ and 101.3MPa for N₂O₄
Explanation: To determine the partial pressures of each gas after the increase of pressure, it can be used the equilibrium constant Kp.
For the reaction 2NO₂ ⇄ N₂O₄, the equilibrium constant is:
Kp = 
where:
P(N₂O₄) and P(NO₂) are the partial pressure of each gas.
Calculating constant:
Kp = 
Kp = 0.0104
After the weights, the total pressure increase to 200 MPa. However, at equilibrium, the constant is the same.
P(N₂O₄) + P(NO₂) = 200
P(N₂O₄) = 200 - P(NO₂)
Kp =
0.0104 = ![\frac{200 - P(NO_{2}) }{[P(NO_{2} )]^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B200%20-%20P%28NO_%7B2%7D%29%20%20%7D%7B%5BP%28NO_%7B2%7D%20%29%5D%5E%7B2%7D%7D)
0.0104![[P(NO_{2} )]^{2}](https://tex.z-dn.net/?f=%5BP%28NO_%7B2%7D%20%29%5D%5E%7B2%7D)
+ 
- 200 = 0
Resolving the second degree equation:
= 
= 98.7
Find partial pressure of N₂O₄:
P(N₂O₄) = 200 - P(NO₂)
P(N₂O₄) = 200 - 98.7
P(N₂O₄) = 101.3
The partial pressures are = 98.7 MPa and P(N₂O₄) = 101.3 MPa
