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Nadusha1986 [10]
4 years ago
6

Limit sodium intake to less than ____________ per day. Limit saturated fat intake to less than ____________ of daily kilocalorie

s. Limit intake of added sugars to less than ____________ of daily kilocalories. Limit intake of alcohol to less than ____________ drink(s) per day for men or less than ____________ drink(s) per day for women.
Chemistry
1 answer:
kotykmax [81]4 years ago
4 0

Answer:

Limit sodium intake to less than <em><u>2,300mg</u></em> per day. Limit saturated fat intake to less than <em><u>10% </u></em>of daily kilocalories. Limit intake of added sugars to less than<em><u> 5% </u></em>of daily kilocalories. Limit intake of alcohol to less than <em><u>3 drinks </u></em>per day for men or less than <em><u>2 drinks</u></em> per day for women.

Explanation:

The human body has been designed such that there are dietary requirements and benefits these intakes give the body. However, excess consumption of certain foods, could be far more detrimental both on the short and long run.

Sodium is majorly consumed in the form of salt (Sodium chloride). When eaten in the right quantity, it serves as an electrolyte which maintains fluid balance in the body however, when taken in excess, it pulls too much fluid, leading to high blood pressure. The recommended salt intake therefore, is less than 2,300mg daily.

Saturated fat when consumed, is a good source for the body to convert diet to energy, keeping the blood sugar levels constant. Lard, fatty meats are examples of saturated fat. However, when consumed in large amounts, saturated fats can cause cholesterol build up in blood vessels, increasing the risk of heart disease. Its intake should therefore be limited to less than 10% of daily kilocalories.

Added sugars are sources of energy to the body however, when taken in large amounts, could impede normal metabolism in the body. Added sugars should be restricted to less than 5% of daily kilocalories in diet.

Alcohol intake such as in wine, when done in moderation, has been shown to reduce the risk of heart diseases. However, when taken in excess, tolerance builds and exposes the body to the risk of conditions such as liver disease, alcohol use disorder.

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What is the pH of a solution with a concentration of 1.0 * 10-4 M?
Maksim231197 [3]

Answer: pH = 10

Explanation: First solve for pOH using the equation pOH=-log[OH-] = 4

Then plug the pOH in the equation, pH + pOH =14

then solve for pH. pH =14 - 4 = 10

7 0
3 years ago
Read 2 more answers
2FeCl3 + MgO -&gt; Fe2O3 + 3MgCl2<br> Convert 3.00 moles of MgO to moles of Fe2O3
nikitadnepr [17]

71.8 g of iron (III) oxide (Fe₂O₃) were produced from 3 moles of magnesium oxide (MgO).

Explanation:

We have the following chemical reaction:

2 FeCl₃ + 3 MgO → Fe₂O₃ + 3 MgCl₂

We see from the chemical reaction that 3 moles of magnesium oxide (MgO) will produce 1 mole of iron (III) oxide (Fe₂O₃).

number of moles = mass / molar weight

mass = number of moles × molar weight

mass of Fe₂O₃ = 1 × 71.8 = 71.8 g

Learn more about:

number of moles

brainly.com/question/13981579

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6 0
3 years ago
A 0.600 g sample of diprotic acid H2X is dissolved in water, and titrated to the equivalence point with 40.0 mL of 0.200 M NaOH.
9966 [12]

Answer:

150 g/mol

Explanation:

Let's consider the complete neutralization of a diprotic acid H₂X with NaOH.

H₂X + 2 NaOH → Na₂X + 2 H₂O

40.0 mL of 0.200 M NaOH. were required to reach the endpoint. The reacting moles of NaOH are:

0.0400 L × 0.200 mol/L = 8.00 × 10⁻³ mol

The molar ratio of H₂X to NaOH is 1:2. The reacting moles of H₂X are 1/2 × 8.00 × 10⁻³ mol = 4.00 × 10⁻³ mol.

4.00 × 10⁻³ moles of H₂X have a mass of 0.600 g. The molar mass of H₂X is:

0.600 g/4.00 × 10⁻³ mol = 150 g/mol

8 0
3 years ago
If our eyes could see a slightly wider region of the electromagnetic spectrum, we would see a fifth line in the Balmer series em
erica [24]

Answer: Wavelength  associated with the fifth line is 397 nm

Explanation:

E=\frac{hc}{\lambda}

\lambda = Wavelength of radiation

E= energy

For fifth line in the H atom spectrum in the balmer series will be from n= 2 to n=7.

Using Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )\times Z^2

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant =10973731.6m^{-1}

n_f = Higher energy level = 7

n_i= Lower energy level = 2 (Balmer series)

Putting the values, in above equation, we get

\frac{1}{\lambda}=10973731.6\times \left(\frac{1}{2^2}-\frac{1}{7^2} \right )\times 1^2

\frac{1}{\lambda}=2.52\times 10^{6}m

\lambda}=3.97\times 10^{-7}m=397 nm      1nm=10^{-9}m

Thus wavelength λ associated with the fifth line is 397 nm

7 0
4 years ago
The natural abundance of 3he is 0.000137 %. how many protons, neutrons, and electrons are in an atom of 3he?
jok3333 [9.3K]
2 protons+, 1 neutron, and 2electrons-
3 0
4 years ago
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