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Solnce55 [7]
3 years ago
11

If one uses an analytical balance to measure out a small quantity of reagent, and the mass is 0.0256 g, then how many significan

t figures are present?
Chemistry
1 answer:
vladimir1956 [14]3 years ago
3 0

Answer:

3

Explanation:

There are 3 significant figures and four decimal places. How do you know how many significant figures? Now let us convert the given number to standard form; we have 2.56*10^-2. Only the two significant figures were shown.

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Predict what the population of the United States will be in the year 2010
s344n2d4d5 [400]

Answer:

308.7 million

Explanation:

is my prediction

5 0
3 years ago
Upon arrival we needed to hunt in this new land we only had five refills and they needed 50 g of gunpowder to be shot once. We o
emmasim [6.3K]

Answer:

Explanation:

Upon arrival we needed to hunt in this new land we only had five refills and they needed 50 g of gunpowder to be shot once. We only have 15 pounds of gunpowder. It is taking six shots to kill one of these wild turkeys. How many turkeys can be shot with 15 pounds of gunpowder?

If we had plenty of refills, and it takes 6 shots to kill a wild turkey at 50 gms of gunpowder per shot, then each turkey requires 6X50 =300gms of gunpowder.  We have 15X454 gms of gunpowder and have the potential to kill 15X454/300=22.7 or 22 turkeys.and it takes 6 shots to kill a wild turkey.

The limiting reagent is the number of refills, and withonly 5, we are out of luck and can't kill one turkey

6 0
2 years ago
An experiment shows that a 250 −mL gas sample has a mass of 0.436 g at a pressure of 742 mmHg and a temperature of 27 ∘C.
icang [17]

Answer:

41.9 g/ mol hope that helps you out

Explanation:

d=p.m/ r.t

8 0
3 years ago
3. The diet of white-tailed deer consists primarily of shrubs. Sika are
olga_2 [115]
Sika have more food choices because they eat both grasses and shrubs, compared to the white-tailed dear who only eats shrubs.
3 0
2 years ago
Given that you started with 28.5 g of K3PO4, how many grams of KNO3 can be<br> produced?
Irina18 [472]

Mass of KNO₃ : = 40.643 g

<h3>Further explanation</h3>

Given

28.5 g of K₃PO₄

Required

Mass of KNO₃

Solution

Reaction(Balanced equation) :

2K₃PO₄ + 3 Ca(NO₃)₂ = Ca₃(PO₄)₂ + 6 KNO₃

mol K₃PO₄(MW=212,27 g/mol) :

= mass : MW

= 28.5 : 212,27 g/mol

= 0.134

Mol ratio of K₃PO₄ : KNO₃ = 2 : 6, so mol KNO₃ :

= 6/2 x mol K₃PO₄

= 6/2 x 0.134

= 0.402

Mass of KNO₃ :

= mol x MW KNO₃

= 0.402 x 101,1032 g/mol

= 40.643 g

8 0
3 years ago
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