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Solnce55 [7]
2 years ago
11

If one uses an analytical balance to measure out a small quantity of reagent, and the mass is 0.0256 g, then how many significan

t figures are present?
Chemistry
1 answer:
vladimir1956 [14]2 years ago
3 0

Answer:

3

Explanation:

There are 3 significant figures and four decimal places. How do you know how many significant figures? Now let us convert the given number to standard form; we have 2.56*10^-2. Only the two significant figures were shown.

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Which of the following is an example of a “nature vs. nurture" question?
Naily [24]

Answer:

The answer to your question is D

5 0
3 years ago
3,010,000 into scientific notation
skelet666 [1.2K]

Answer:

3.01 x 10 to the power of 6

Explanation:

Step 1

To find a, take the number and move a decimal place to the right one position.

Original Number: 3,010,000

New Number: 3.010000

Step 2

Now, to find b, count how many places to the right of the decimal.

3 0
2 years ago
Read 2 more answers
Need help with this can some please help
vekshin1
I believe you would just put a 2 in front of NH3 and keep the other ones as 1
7 0
3 years ago
Is there a phobia for chemical reactions specifically?
gizmo_the_mogwai [7]

Answer:

chemonoia

Explanation:

Many people have a strong fear of “chemicals” that belies the evidence. It's called chemonoia – and it may be damaging their health. If you were paranoid, you might think there really was something in the water that's damaged our sense of reason.

8 0
2 years ago
Calcium carbide, CaC2, is manufactured by reducing lime with carbon at high temperature. (The carbide is used in turn to make ac
sweet-ann [11.9K]

The energy of the carbide released is 7262.5MJ.

<h3>What is the energy?</h3>

We know that the reaction between calcium  oxide and carbon occurs in accordance with the reaction; CaO(s)+3C(s)----- > CaC_{2} (s)+CO(g). The reaction is seen to produce 464.8kJ of energy per mole of carbide produced.

Number of moles of CaC_{2} produced = 1000 * 10^3 g/64 g/mol

= 15625 moles of calcium carbide

If 1 mole of CaC_{2} transfers  464.8 * 10^3 J

15625 moles of calcium carbide transfers 15625 moles  * 464.8 * 10^3 J/ 1 mol

= 7262.5MJ

Learn more about reaction enthalpy:brainly.com/question/1657608

#SPJ1

7 0
1 year ago
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