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Solnce55 [7]
2 years ago
11

If one uses an analytical balance to measure out a small quantity of reagent, and the mass is 0.0256 g, then how many significan

t figures are present?
Chemistry
1 answer:
vladimir1956 [14]2 years ago
3 0

Answer:

3

Explanation:

There are 3 significant figures and four decimal places. How do you know how many significant figures? Now let us convert the given number to standard form; we have 2.56*10^-2. Only the two significant figures were shown.

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What is the most common isotope for element X
ankoles [38]

Answer:

isotope 2

Explanation:

it has the highest percentage abundance

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2 years ago
Prove that circle p and circle q are similar.
abruzzese [7]
All circles are similar.
8 0
3 years ago
Which of these is not a gas? hydrogen, oxygen, gravity, or helium
katrin2010 [14]

Answer:

I think that Gravity is not considered a gas but it can at the same time

Explanation:

Gasses are affected by gravity, as above video will prove. ... Yes, there is a attractive force between the gas molecules and gravity !

The rest are for sure gases

8 0
3 years ago
Read 2 more answers
The concentration of Rn−222 in the basement of a house is 1.45 × 10−6 mol/L. Assume the air remains static and calculate the con
bonufazy [111]

<u>Answer:</u> The concentration of radon after the given time is 3.83\times 10^{-30}mol/L

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

We are given:

t_{1/2}=3.82days

Putting values in above equation, we get:

k=\frac{0.693}{3.82}=0.181days^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,  

k = rate constant = 0.181days^{-1}

t = time taken for decay process = 3.00 days

[A_o] = initial amount of the reactant = 1.45\times 10^{-6}mol/L

[A] = amount left after decay process =  ?

Putting values in above equation, we get:

0.181days^{-1}=\frac{2.303}{3.00days}\log\frac{1.45\times 10^{-6}}{[A]}

[A]=3.83\times 10^{-30}mol/L

Hence, the concentration of radon after the given time is 3.83\times 10^{-30}mol/L

7 0
3 years ago
HELPPP!!! what is the volume (in liters) of a 5.72 gram sample of 02 at STP? (Hint: remember to change grams of oxygen to moles
Alona [7]

Answer:

4L

Explanation:

To obtain the volume of O2 at stp, first, we need to determine the number of mole of O2.

From the question given above,

Mass of O2 = 5.72g

Molar Mass of O2 = 32g/mol

Number of mole =Mass/Molar Mass

Number of mole of O2 = 5.72/32

Number of mole of O2 = 0.179 mole

Now, we can calculate the volume of O2 at stp as follow:

1 mole of a gas occupy 22.4L at stp.

Therefore, 0.179 mole of O2 will occupy = 0.179 x 22.4 = 4L

Therefore, the volume occupied by the sample of O2 is 4L

7 0
3 years ago
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