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snow_tiger [21]

3 years ago

6

When you listen to the radio watch TV or cook food in the microwave you're using a device that makes use of man-made electric ma

gnetic waves which statement about electromagnetic waves is false

1 answer:

saul85 [17]3 years ago

5 0

Answer:

the false statements

Explanation:

Radio waves, Tw or microndasm are produced by the man with different instruments, so to detect them we use an artifact that detects electrical waves

From the false statements

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The height of the tide measured at a seaside community varies according to the number of hours t after midnight. If the height h

antoniya [11.8K]

Explanation:

Given that, the height of the tide measured at a seaside community varies according to the number of hours t after midnight. The height is given by the equation as :

$h=-\dfrac{1}{2}t^2+6t-9$

When the tide first be at 6 ft, put h = 6 ft in above equation as :

$-\dfrac{1}{2}t^2+6t-9=6$

$-t^2+12t-18=0$

On solving the above equation to find the value of t. It is equal to :

t = 3.551 seconds

or

t = 8.449 seconds

So, the tide of 6 ft is at 3.551 seconds and 8.449 seconds. Hence, this is the required solution.

6 0

2 years ago

Why do we eat today

earnstyle [38]

Because if we don't you'll be hungry, if you don't eat for about a month you'll die

3 0

3 years ago

Read 2 more answers

A gas occupies 0.60 m3 at a 5.0 atm. If the temperature of the gas remains the same and the pressure decreases to 2.5 atm, what

Naddika [18.5K]

Answer:

its 6 :) hdgdgsvhdhs

Explanation:

hdhdhscdhsjsvdjsjwjshd

8 0

3 years ago

A train at a constant 79.0 km/h moves east for 27.0 min, then in a direction 50.0° east of due north for 29.0 min, and then west

ivolga24 [154]

Answer:

Magnitude of avg velocity, $|v_{avg}| = 18.9 km/h$

$\theta' = 56.85^{\circ}$

Given:

Constant speed of train, v = 79 km/h

Time taken in East direction, t = 27 min = $\frac{27}{60} h$

Angle, $\theta = 50^{\circ}$

Time taken in $50^{\circ}$ east of due North direction, t' = 29 min = $\frac{29}{60} h$

Time taken in west direction, t'' = 37 min = $\frac{27}{60} h$

Solution:

Now, the displacement, 's' in east direction is given by:

$\vec{s} = vt = 79\times \frac{27}{60} = 35.5\hat{i} km$

Displacement in $50^{\circ}$ east of due North for 29.0 min is given by:

$\vec{s'} = vt'sin50^{\circ}\hat{i} + vt'cos50^{\circ}\hat{j}$

$\vec{s'} = 79(\frac{29}{60})sin50^{\circ}\hat{i} + 79(\frac{29}{60})cos50^{\circ}\hat{j}$

$\vec{s'} = 29.25\hat{i} + 24.54\hat{j} km$

Now, displacement in the west direction for 37 min:

$\vec{s''} = - vt''hat{i} = - 79\frac{37}{60} = - 48.72\hat{i} km$

Now, the overall displacement,

$\vec{s_{net}} = \vec{s} + \vec{s'} + \vec{s''}$

$\vec{s_{net}} = 35.5\hat{i} + 29.25\hat{i} + 24.54\hat{j} - 48.72\hat{i}$

$\vec{s_{net}} = 16.03\hat{i} + 24.54\hat{j} km$

(a) Now, average velocity, $v_{avg}$ is given:

$v_{avg} = \frac{total displacement, \vec{s_{net}}}{total time, t}$

$v_{avg} = \frac{16.03\hat{i} + 24.54\hat{j}}{\frac{27 + 29 + 37}{60}}$

$v_{avg} = 10.34\hat{i} + 15.83\hat{j}) km/h$

Magnitude of avg velocity is given by:

$|v_{avg}| = \sqrt{(10.34)^{2} + (15.83)^{2}} = 18.9 km/h$

(b) angle can be calculated as:

$tan\theta' = \frac{15.83}{10.34}$

$\theta' = tan^{- 1}\frac{15.83}{10.34} = 56.85^{\circ}$

6 0

3 years ago

ln the constellation of Orion, you can see a group of stars and other objects that appear in the shape of a sword. Ln the middle

bagirrra123 [75]

Answer:

Nebula

Explanation:

Given that in the constellation of Orion, you can see a group of stars and other objects that appear in the shape of a sword. Ln the middle of the sword, a bright "fuzzy star" appears. Astronomers looking at this object through telescopes refer to it as a "stellar nursery." Another name for this object is called NEBULA.

The space where new stars are forming anew is known as nebulae

7 0

3 years ago