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goblinko [34]
3 years ago
10

What are the possible values of n and ml for an electron in a 3d orbital?

Physics
1 answer:
jeka943 years ago
6 0
In quantum mechanics, an atomic orbital<span> is a mathematical function that </span>describes<span> the wave-like behavior of either one electron or a pair of electrons in an </span>atom<span>. This function can be used to calculate the probability of finding any electron of an </span>atom<span> in any specific region around the </span>atom's<span> nucleus.</span>
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Explanation:

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Mt. Everest is 29,028 feet high. How many miles is this?
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A beam of electrons moving in the x-direction enters a region where a uniform 208-G magnetic field points in the y-direction. Th
GREYUIT [131]

Answer:

1.26\cdot 10^7 m/s

Explanation:

When a charged particle moves perpendicularly to a magnetic field, the force it experiences is:

F=qvB

where

q is the charge

v is its velocity

B is the strength of the magnetic field

Moreover, the force acts in a direction perpendicular to the motion of the charge, so it acts as a centripetal force; therefore we can write:

qvB=m\frac{v^2}{r}

where

m is the mass of the particle

r is the radius of the orbit of the particle

The equation can be re-arranges as

v=\frac{qBr}{m}

where in this problem we have:

q=1.6\cdot 10^{-19}C is the magnitude of the charge of the electron

B=208 G=208\cdot 10^{-4}T is the strength of the magnetic field

The beam penetrates 3.45 mm into the field region: therefore, this is the radius of the orbit,

r=3.45 mm = 3.45\cdot 10^{-3} m

m=9.11\cdot 10^{-31} kg is the mass of the electron

So, the electron's speed is

v=\frac{(1.6\cdot 10^{-19})(208\cdot 10^{-4})(3.45\cdot 10^{-3})}{9.11\cdot 10^{-31}}=1.26\cdot 10^7 m/s

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3 years ago
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Answer:

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Explanation:

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11111nata11111 [884]

Answer:

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3 years ago
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