All categories

3 years ago

1. Calculate the momentum of each car before the collision: SHOW YOUR WORK!

Physics

1 answer:

a_sh-v [17]3 years ago

3 0

Answer:

Momentum of red car = 5kgm/s

Momentum of blue car = 0kgm/s

Explanation:

Momentum = mass × velocity

For the red car

Mass = 1kg

Velocity = 5m/s

Momentum of the red car = 1kg × 5m/s

Momentum of the red car = 5kgm/s

For the blue car.

Mass = 1kg

Velocity = 0m/s(shows that the blue car is stationery)

Momentum = 1kg ×0m/s

Momentum of the blue car = 0kgm/s

You might be interested in

You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t

Sladkaya [172]

Answer:

0.767

Explanation:

The work done on the truck by the frictional drag force is given by

$W=-Fd$

where

F is the magnitude of the frictional force

d = 38.0 m is the maximum displacement allowed for the truck

The negative sign is due to the fact that the force of friction is opposite to the motion of the truck

The force of friction can also be written as:

$F=\mu mg$

where

$\mu$ is the coefficient of kinetic friction between the truck and the lane

m is the mass of the truck

g is the acceleration of gravity

So we can rewrite the work done as

$W=-\mu mg d$ (1)

According to the work-energy theorem, the work done by friction is equal to the change in kinetic energy of the truck:

$W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2$ (2)

where

v = 0 is the final velocity of the truck

u = 23.9 m/s is the initial velocity of the truck

By combining (1) and (2) we get

$-\frac{1}{2}mu^2 = -\mu mg d$

And solving for $\mu$ , we find the minimum coefficient of kinetic friction able to stop the truck in a distance d:

$\mu = \frac{u^2}{2gd}=\frac{23.9^2}{2(9.8)(38.0)}=0.767$

7 0

3 years ago

I need help ASAP pleasee!!!

Vera_Pavlovna [14]

Answer: when in doubt go with B

Explanation:

3 0

3 years ago

Read 2 more answers

A hair dryer is basically a duct of constant diameter in which a few layers of electric resistors are placed. A small fan pulls

Mars2501 [29]

Answer:

Therefore % increase in velocity is 18.23 %

Explanation:

we use the equality of mass flow rate and the areas

$m_1 = m_2\\p_1v_1 = p_2v_2\\p_1A_1v_1 = p_2A_2v_2\\v_2 = \frac{p_1}{p_2} v_1$

The percentage increase in velocity is

Δ v% = $\frac{v_2 - v_1}{v_1} \\$ 100%

= $\frac{p_1}{p_2} v_1 - v_1$ .100%

= $\frac{\frac{1.2}{1.015} - 1}{1}$ . 100%

= Therefore % increase in velocity is 18.23 %

5 0

3 years ago

In non-ferromagnetic materials, most of the electrons are _____.

OleMash [197]

It hink that it is the 2nd one

7 0

3 years ago

Read 2 more answers

Once Kate's kite reaches a height of 50 ft (above her hands), it rises no higher but drifts due east in a wind blowing 7 ft d

Margaret [11]

Answer:

dz = 7.136 (answer)

Explanation:

given height for kate's kite = 50 ft (say y)

due to drift it move towards east = dx = 7 ft

string maximum length = 107 ft ( say z)

we have to find change in z

that is dz

it will form a right angle triangle for x , y and z where x is base y is height and z is hypotenuse

so we get according to Pythagoras Theorem

$z^2 = x^2+y^2\\$ ...............(i)

by derivative both side consider y as constant

$2zdz = 2xdx\\dz = {xdx }/z$

from (i) equation

$x = \sqrt{z^2-y^2}$

$dz = \sqrt{z^2-y^2}dx/z$

now put the value and find dz

$dz = (\sqrt{120^2-50^2)}7/107\\ =((\sqrt{14400 -2500} )\times7)/107$

after solving these we get

$dz =\frac{109.08\times7}{107}$

dz = 7.136 (answer)

7 0

3 years ago