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Anna71 [15]
3 years ago
7

three moles of sodium carbonate are mixed with two moles of lead nitrate in aqueous solution, leading to formation of a solid pr

ecipitate. how many moles of spectator ions remain in solution, assuming 100% yield of the precipitate?
Chemistry
1 answer:
aleksandrvk [35]3 years ago
6 0

There are 4 moles of spectator ions that remain in solution.

The equation of the reaction is;

Na2CO3(aq) + Pb(NO3)2(aq) -------> PbCO3(s) + 2NaNO3(aq)

We have to determine the limiting reactant. This is the reactant that yields the least amount of product. Note that the spectator ions are Na^+ and NO3^- that form NaNO3.

For Na2CO3

1 mole of Na2CO3 yields 2 moles of NaNO3

3 moles of Na2CO3 yields  3 × 2/1 = 6 moles of NaNO3

For Pb(NO3)2

1 mole of Pb(NO3)2 yields 2 moles of NaNO3

2 moles of Pb(NO3)2 yields 2 × 2/1 = 4 moles of NaNO3

We can see that Pb(NO3)2 is the limiting reactant.

Since [NaNO3] = [Na^+] = [NO3^-], it follows that there are 4 moles of spectator ions that remain in solution.

Learn more: brainly.com/question/22885959

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Step-by-step explanation:

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Marcia's teacher plotted the mass of the sample along the x-axis and volume along the y-axis.

The mass is the independent variable, because that is <em>what the teacher varied</em>.

The volume is the <em>dependent variable</em>, because it <em>depends</em> on the mass.

Sample number is <em>wrong</em>, because it is not a variable.

Substance is <em>wrong</em>, because all samples consist of the same substance.

Density is <em>wrong</em>, because it is constant. It is the slope of the graph.

3 0
3 years ago
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Answer:

51.2g of CO2

Explanation:

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3 years ago
The size (radius) of an oxygen molecule is about 2.0 ×10−10m. Make a rough estimate of the pressure at which the finite volume o
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Answer:

Explanation:

We can calculate the volume  of the oxygen molecule as the radius of oxygen molecule is given as 2×10⁻¹⁰m.

We know that volume=4/3×πr³

volume =4/3×π(2.0×10⁻¹⁰m)³

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we know the ideal gas equation as:

PV=nRT

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R=k×Na

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PV=Nkt

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v is volume  of gas

T is temperature of gas

N is numbetr of molecules

Na is avagadros number

k is boltzmann constant =1.38×10⁻²³J/K

R is real gas constant

So to calculate pressure using the  formula;

PV=NkT

P=NkT/V

Since there is only one molecule of oxygen so N=1

P=[1×1.38×10⁻²³J/K×300]/[33.40×10⁻³⁰m³

p=12.39×10⁷Pascal

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