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jekas [21]
3 years ago
15

how many grams of potassium chloride, KCL(molar mass is 74.55g/mol) are produced if 25 grams of potassium chlorate KClo^3 decomp

ose
Chemistry
1 answer:
JulsSmile [24]3 years ago
6 0

Answer:

                     Mass = 15.20 g of KCl

Explanation:

                    The balance chemical equation for the decomposition of KClO₃ is as follow;

                                            2 KClO₃ = 2 KCl + 3 O₂

Step 1: Calculate moles of KClO₃ as;

Moles = Mass / M/Mass

Moles = 25.0 g / 122.55 g/mol

Moles = 0.204 moles

Step 2: Find moles of KCl as;

According to equation,

                  2 moles of KClO₃ produces  =  2 moles of KCl

So,

               0.204 moles of KClO₃ will produce  =  X moles of KCl

Solving for X,

                       X = 2 mol × 0.204 mol / 2 mol

                       X = 0.204 mol of KCl

Step 3: Calculate mass of KCl as,

Mass = Moles × M.Mass

Mass = 0.204 mol × 74.55 g/mol

Mass = 15.20 g of KCl

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The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Using equation PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

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