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a = (Vf - Vi)/t ; where distance d = [2(t)]/(4+t), t = 5secs, and Vi = 0
a = [(2t)/(4+t)]/t <---- working equation
a = {[2(5)]/9}/5 <---- cancel 5
a = 2/9 ft/s^2 <---- Answer
Magnetic field describea magnet's ability to act at a distance
Answer:
The answer is 10Nm
Explanation: I ended up just messing around with the numbers, I multiplied 5 and 2 got 10 as my answer and it was right.
The expression, in terms of defined quantities and g is therefore Fu =((mg/2) +2 mp) g
<h3>
What is a Scale?</h3>
This can be defined as a balance or any of various other instruments or devices for weighing.
The expression in terms of defined quantities and g, for the force that the scale under left pillar shows that Fu =((mg/2) +2 mp) g .
Read more about Force here brainly.com/question/4515354