The height of the table above the ground is 0.45 m.
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Horizontal velocity (u) = 3 m/s
- Time (t) = 0.3 s
- Acceleration due to gravity (g) = 10 m/s²
- Height (h) =?
<h3>How to determine the height </h3>
The height of the table can be obtained by using the following formula:
h = ½gt²
h = ½ × 10 × 0.3²
h = 5 × 0.09
h = 0.45 m
Thus, the height of the table is 0.45 m
Learn more about motion under gravity:
brainly.com/question/26275209
Answer:
Explanation:
A 40kg child throw stone of 0.5kg
At a direction of 5m/s
Recoil can be calculated using recoil of a gun formula
m_1•v_1 + m_2•v_2
m_1•v_1 = -m_2•v_2
The negative sign show that the momentum of the boy is directed oppositely to that of the stone
m_1 Is mass of boy
v_1 is the recoil velocity of the boy
m_2 is mass of stone
v_2 is the velocity of stone
Then,
m_1•v_1 = -m_2•v_2
40•v_1 = -0.5 × 5
40•v_1 = -2.5
v_1 = -2.5 / 40
v_1 = -0.0625 m/s
The recoil velocity of the boy is 0.0625 m/s
Answer:
Team A wins the frame with three points. The opposing team gets zero points for the frame.
Explanation:
Answer:
it would make sense because a larger body could produce more body heat.
Answer:
PE=0.92414J and KE=0.28175J
Explanation:
Gravitational potential energy=mass*gravity*height
PE=mgh
Data,
M=0.046kg
H=2.05m
g=9.8m/s^2
PE=0.046kg * 9.8m/s^2 * 2.05m
PE =0.92414J
KE=1/2mv^2
M=0.046kg
V=3.5m/s
KE=[(0.046kg)*(3.5m/s)^2]\2
KE=0.28175J
