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3 years ago

Koala bears can eat only certain kinds of Australian eucalyptus leaves. Koalas are considered _____.

2 answers:

3 0

They are marsupials that are considered "specialist eaters" since they only eat a certain type of leaf. While generalist feeders aren't as picky as the koala bears. I hope this helps!

defon3 years ago

3 0

Answer:

Herbivore Marsupials

Explanation:

Koalas are the herbivore marsupials that are found to be dwelling on the trees, and are dominantly found in the continent of Australia. They are very selective in terms of food, and are able to eat only certain types of plant leaves but not all. They obtain relatively less nutritious food, thereby receives less amount of energy. Due to this, the Koalas are mostly lazy and spend most of their time by sleeping and sitting.

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A particle (mass = 2.0 mg, charge = −6.0 μC) moves in the positive direction along the x axis with a velocity of 3.0 km/s. It en

Virty [35]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The acceleration would be $a = 0.003* 6 =0.018\ m/s^2$

Explanation:

The objective of this solution is to obtain the acceleration of the particle

Now looking at Newton law which is mathematically represented as

$F = ma$

Where F is the force experience by a particle

m is the mass of the particle

a is the acceleration of the particle

And also this force is equivalent to magnetic force in a magnetic field which is mathematically represented as

$F = qvB$

Where q is the charge of the particle

v is the velocity of the charge

B is the magnetic field the charge is under it influence

Now equating this two formulas

$ma = qvB$

Making a the subject we have

$a = \frac{qvB}{m}$

In the question the direction of the is in the positive x-axis which is $i$ hence the direction would be in the $i$ direction

So substituting $(2.0i +3.0j+4.0k)mT = (2.0i +3.0j+4.0k)*10^{-3}T$ for B

$a = \frac{q}{m} * v (2.0i +3.0j +4.0k)*10^{-3}$

Substituting $3.0 Km /s = 3.0*10^{3}\ m/s$ for v and $-6.0 \muC = -6.0*10^{-6} C$ for q

$a = \frac{-6.0*10^{-6}}{2.0*10^{-3}} * 3.0*10^{3} *(2i+3j+4k) *10^{-3}$

$a = 0.003 * 3i(2i+3j+4k)$

$a = 0.003 *((3*2)i \ \cdot i \ +(3*3) i \ \cdot \ j \ + (3*4)i \ \cdot \ k)$

According to vector multiplication

$i \cdot i = j \cdot j = k\cdot k = 1\\\\and \ i\cdot j = i\cdot k = 0$

$a = 0.003* 6 =0.018\ m/s^2$

8 0

3 years ago

Suppose there was 2 Newtons what would the mass of the cart be?

vlada-n [284]

2 pounds.................

7 0

3 years ago

A particle moves along a straight line with an acceleration of a = 5>(3s 1>3 + s 5>2) m>s2, where s is in meters. De

Len [333]

Answer:

v=1.295

Explanation:

What we are given:

a=5÷(3s^(1/3)+s^(5/2)) m/s^2

Start by using equation a ds = v dv

This problem requires a numeric method of solving. Therefore, you can integrate v ds normally, but you must use a different method for a ds The problem should look like this:

$\int\limits^a_b {x} \, dx$

a=2

b=1

x=5÷(3s^(1/3)+s^(5/2)) m/s^2

dx=dv

Integrate the left side the standard method.

$\int\limits^a_b {x} \, dx$

a=v

b=0

dx=dv

Integrating

=v^2/2

Use Simpson's rule for the right site.

$\int\limits^a_b {x} \, dx$

a=b

b=a

x=f(x)

f(x)=b-a/6*(f(a)+4f(a+b/2)+f(b)

If properly applied. you should now have the following equation:

v^2/2=5[(1/6*(0.25+4(0.162)+(0.106)]

=0.8376

Solve for v.

v=1.295

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3 years ago

A disturbance that moves through a solid, liquid, gas, or a vacuum is defined as __________.

11Alexandr11 [23.1K]

A wave as long as matter is not being transported

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3 years ago

Read 2 more answers

Which three statements describe Electromagnetic waves

Brums [2.3K]

Answer:

As you learned in Wave Motion, all waves have amplitude, wavelength, velocity and frequency.hope that helps

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3 years ago