First, we need to find the acceleration
F = ma
9850 N = (815 kg + 61 kg)a
a = 11.24
the read of the scale during the acceleration is :
mg + ma
= (61 kg x 9.8) + (61 kg x 11.24)
= 1283.4 N
hope this helps
Okay. There is a simple formula to go with this where:
p = mv
P: Momentum.
M: Mass.
V: Velocity
Sub the numbers in and solve for M.
10.0 = m(1.5)
10.0/1.5 = m
6.67 kg = m
Therefore the mass of the ball is 6.67kg.
Answer:
Voltage-gated K+ channels
Answer:
4.88 m/s
Explanation:
Vertical component would be 12 * sin 24 = 4.88 m/s
Horizontal is 12 * cos 24
Answer:
Maximum height reached by the ball is 32 meters.
Explanation:
It is given that,
If a baseball is project upwards from the ground level with an initial velocity of 32 feet per second, then it's height is a function of time. The equation is given as :
...........(1)
t is the time taken
s is the height attained as a function of time.
Maximum height achieved can be calculated as :


-16 t + 32 = 0
t = 2 seconds
Put the value of t in equation (1) as :

s = 32 meters
So, the maximum height reached by the ball is 32 meters. Hence, this is the required solution.