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Naddik [55]
3 years ago
10

Koala bears can eat only certain kinds of Australian eucalyptus leaves. Koalas are considered _____.

Physics
2 answers:
murzikaleks [220]3 years ago
3 0
They are marsupials that are considered "specialist eaters" since they only eat a certain type of leaf. While generalist feeders aren't as picky as the koala bears. I hope this helps!
defon3 years ago
3 0

Answer:

Herbivore Marsupials

Explanation:

Koalas are the herbivore marsupials that are found to be dwelling on the trees, and are dominantly found in the continent of Australia. They are very selective in terms of food, and are able to eat only certain types of plant leaves but not all. They obtain relatively less nutritious food, thereby receives less amount of energy. Due to this, the Koalas are mostly lazy and spend most of their time by sleeping and sitting.

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vazorg [7]
First, we need to find the acceleration
F = ma
9850 N = (815 kg + 61 kg)a
a = 11.24

the read of the scale during the acceleration is :


mg + ma

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hope this helps
 
7 0
3 years ago
if a ball is rolling at a velocity of 1.5 m/sec and has the momentum of 10.0 kg m/sec, what is the mass of the ball?
PolarNik [594]
Okay. There is a simple formula to go with this where:

p = mv

P: Momentum.
M: Mass.
V: Velocity

Sub the numbers in and solve for M.

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6 0
3 years ago
Which ion channels mediate the falling phase of an action potontial?
White raven [17]

Answer:

Voltage-gated K+ channels

4 0
3 years ago
A ball is traveling 24° above the horizontal at a speed of 12 m/s. What is the vertical component of its speed?
victus00 [196]

Answer:

4.88 m/s

Explanation:

Vertical component would be  12 * sin 24  =  4.88 m/s

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3 0
2 years ago
If a basball is project upwards from the ground level with an initial velovaity of 32 feet per second, then it's height is a fun
inessss [21]

Answer:

Maximum height reached by the ball is 32 meters.

Explanation:

It is given that,

If a baseball is project upwards from the ground level with an initial velocity of 32 feet per second, then it's height is a function of time. The equation is given as :

s=-8t^2+32t...........(1)

t is the time taken

s is the height attained as a function of time.

Maximum height achieved can be calculated as :

\dfrac{ds}{dt}=0

\dfrac{d(-8t^2+32t)}{dt}=0

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t = 2 seconds

Put the value of t in equation (1) as :

s=-8(2)^2+32(2)

s = 32 meters

So, the maximum height reached by the ball is 32 meters. Hence, this is the required solution.

6 0
4 years ago
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