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Naddik [55]
3 years ago
10

Koala bears can eat only certain kinds of Australian eucalyptus leaves. Koalas are considered _____.

Physics
2 answers:
murzikaleks [220]3 years ago
3 0
They are marsupials that are considered "specialist eaters" since they only eat a certain type of leaf. While generalist feeders aren't as picky as the koala bears. I hope this helps!
defon3 years ago
3 0

Answer:

Herbivore Marsupials

Explanation:

Koalas are the herbivore marsupials that are found to be dwelling on the trees, and are dominantly found in the continent of Australia. They are very selective in terms of food, and are able to eat only certain types of plant leaves but not all. They obtain relatively less nutritious food, thereby receives less amount of energy. Due to this, the Koalas are mostly lazy and spend most of their time by sleeping and sitting.

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Complete Question

The complete question is shown on the first uploaded image

Answer:

The acceleration would be  a = 0.003* 6 =0.018\  m/s^2    

Explanation:

The objective of this solution is to obtain the acceleration of the particle

       Now looking at Newton law which is mathematically represented as

                       F = ma

  Where F is the force experience by a particle

              m is the mass of the particle

              a is the acceleration of the particle

  And also this force is equivalent to magnetic force in a magnetic field which is mathematically represented as

                    F = qvB

Where q is the charge of the particle

             v is the velocity of the  charge

             B is the magnetic field the charge is under it influence

  Now equating this two formulas

                   ma = qvB

 Making a the subject we have

                  a = \frac{qvB}{m}

In the question the direction of the is in the positive x-axis which is i hence the direction would be in the i direction

      So substituting  (2.0i +3.0j+4.0k)mT = (2.0i +3.0j+4.0k)*10^{-3}T for B

                    a = \frac{q}{m} * v (2.0i +3.0j +4.0k)*10^{-3}

      Substituting       3.0 Km /s = 3.0*10^{3}\ m/s  for v  and -6.0 \muC = -6.0*10^{-6} C for q

                     a = \frac{-6.0*10^{-6}}{2.0*10^{-3}} * 3.0*10^{3} *(2i+3j+4k) *10^{-3}

                       a = 0.003 * 3i(2i+3j+4k)

                      a = 0.003 *((3*2)i \ \cdot i \ +(3*3) i \ \cdot \ j  \ + (3*4)i \ \cdot \ k)

According to vector multiplication

                                             i \cdot i = j \cdot j = k\cdot k = 1\\\\and \ i\cdot j = i\cdot k  = 0

     So

               a = 0.003* 6 =0.018\  m/s^2          

     

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Suppose there was 2 Newtons what would the mass of the cart be?
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A particle moves along a straight line with an acceleration of a = 5>(3s 1>3 + s 5>2) m>s2, where s is in meters. De
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Answer:

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Explanation:

What we are given:

a=5÷(3s^(1/3)+s^(5/2)) m/s^2

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\int\limits^a_b {x} \, dx

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<em>Integrating</em>

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Use Simpson's rule for the right site.

\int\limits^a_b {x} \, dx

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If properly applied. you should now have the following equation:

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