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weeeeeb [17]
3 years ago
7

A light-year is a measure of the astronomical distance that light traverses in a vacuum in 1 year. (a) how many kilometers does

light traverse in 1 ly?
Physics
1 answer:
const2013 [10]3 years ago
5 0
<span>A light-year is the total distance that light can travel in 1 year. Since, We know the speed of light (c) in vacuum= 299792458 metres per second And, there are 365.25 days in an year, or t= (365.25*24*60*60) seconds Hence a light-year (d)=c*t =299792458Ă—365.25Ă—24Ă—60Ă—60 metres =9,460,730,472,580,800 metres â‰9.46073Ă—10^15 metres</span>
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Three thermometers are in the same water bath. After thermal equilibrium is established, it is found that the Celsius thermomete
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Answer:

OPTION A, Kelvin Thermometer is Incorrect

Explanation:

Now, if you consider best two out of three results, then celsius and Fahrenheit thermometers read the same value, meaning both are right.

1) K = °C + 273

K = 100°C + 273

k = 373°C

Kelvin Thermometer is Incorrect

2) C = \frac{F - 32}{1.8}

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C = \frac{212 - 32}{1.8} \\\\= 100^\circ C

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3 years ago
Does Anybody Know The Answers?
ch4aika [34]

Answer:

I was going to give you the paper where I saw it but since you are not giving enough points I can not give you so I am only going to give you some of these that are here sorry

Explanation:

1.

9^{2} + 12^2 = x^2\\81 + 144= x^2\\\sqrt{225} = \sqrt{x} \\         15=x\\\\ 2.\\x^2+12^2+=13^2\\x^2+144 =169\\x^2 = 25\\\sqrt{x^2 =\sqrt{25\\\\

x=5

3.\\12^2+32^2 = x^2\\34.176= x

7.

5,12,13

9.

\frac{x}{4} ,\frac{12}{4} ,\frac{20}{4}\\\\\frac{x}{4},3,5  \\\\x=16\\\\12. \\x^2 + 48^2=50^2\\\\x^2=196\\x=14

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5 0
3 years ago
What are the magnitude and direction of the acceleration of an electron at a point where the electric field has magnitude 7400 N
bezimeni [28]

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Explanation: The magnitude of the force required to move the electron is given as

F = ma

The force exerted on the charge by the electric field of intensity (E) is given by

F = Eq

Thus

Eq = ma

a = E * q/ m

Where a = acceleration of charge

E = strength of electric field = 7400N/c

q = magnitude of electronic charge = 1.609 * 10^-6c

m = mass of an electronic charge = 9.109 * 10^-31kg

a = 7400 * 1.609 * 10^-16/ 9.109 * 10^-31

a = 11906.6 * 10^-16 / 9.019 * 10^-31

a = 1.19 * 10^-12 / 9.019 * 10^-31

a = 0.132 * 10^19

a = 1.32 * 10^18m/s²

As stated in the question, the direction of the electric field is due north hence, the direction of it force will also be north thus making the electron experience a force due north ( according to Newton second law of motion)

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3 years ago
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Answer:

c

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Explanation:

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