Answer:
K = 588.3 N/m
Explanation:
From a forces diagram, and knowing that for the maximum value of K, the crate will try to rebound back up (Friction force will point downward):
Fe - Ff - W*sin(22) = 0 Replacing Fe = K*X and then solving for X:
By conservation of energy:
Replacing our previous value for X and solving the equation for K, we get maximum value to prevent the crate from rebound:
K = 588.3 N/m
A kangaroo will stay 0.699s in the air when he jumps.
<h3>What motion does the projectile make?</h3>A projectile is an object that is launched vertically into the air and moves while being pulled by gravity. A projectile is an object that is launched into the air horizontally and moves regardless of gravity.
<h3>How do you determine the rate of descent?</h3>G = -9.81 m/s2 is the acceleration of gravity close to the earth. Simply multiply the acceleration of gravity by the period since the object was released to determine the object's speed (or velocity). In other words, velocity is equal to -9.81 m/s2 * time, or V = gt.
<h3>According to the given information:</h3>From the conversion of energy =
t = √(2h/g)
= √((2 x 2.40) / 9.8)
=0.699 s
A kangaroo will stay 0.699s in the air when he jumps.
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