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3 years ago

When salt is dissolved in water, the salt particles are referred to as the _____.

Chemistry

2 answers:

Sergio039 [100]3 years ago

5 0

The salt is a solid compound and is considered the "Solute" of the solution.

Naddika [18.5K]3 years ago

5 0

The correct answer is D. Solute

Explanation:

In a solution, there are two main substances or elements involved these are the solute and the solvent. The solvent refers to the liquid such as water that dissolves another substance that is the solute. In this way, the solute is the substance that integrates or dissolves in the liquid or solvent and this can be liquid or solid. According to this, in the case presented the water is the solvent, the salt is the solute, and the final substance is the solution. Thus, the salt particles are referred to as the solute.

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How many moles of magnesium chloride can be formed from 4.86 g of Mg and 21.27 g of Cl2?

Hoochie [10]

Answer:

Moles of magnesium chloride can be produced are 0.2 moles

Explanation:

The reaction of Mg with Cl2 is:

Mg + Cl₂ → MgCl₂

Where 1 mole of Mg reacts per mole of Cl₂ to produce MgCl₂.

As the reaction is 1:1, we need to convert the mass of both Mg and Cl₂ to moles. The lower number of moles will determine the moles of MgCl₂ that will be produced:

Moles Mg -Molar mass: 24.3g/mol-:

4.86g * (1mol / 24.3g) = 0.2 moles Mg

Moles Cl₂ -Molar mass: 24.3g/mol-:

21.27g * (1mol / 70.9g) = 0.3 moles Cl₂

As moles of Mg < moles of Cl₂, Mg is limiting reactant and moles of magnesium chloride can be produced are 0.2 moles

8 0

3 years ago

Even though lead is toxic, lead compounds were used in ancient times as white pigments in cosmetics. What is the percentage of l

Gekata [30.6K]

Answer: The mass percent of lead in lead (IV) carbonate is 63.32 %

Explanation:

The given chemical formula of lead (IV) carbonate is $Pb(CO_3)_2$

To calculate the mass percentage of lead in lead (IV) carbonate, we use the equation:

$\text{Mass percent of lead}=\frac{\text{Mass of lead}}{\text{Mass of lead (IV) carbonate}}\times 100$

Mass of lead = (1 × 207.2) = 207.2 g

Mass of lead (IV) carbonate = [(1 × 207.2) + (2 × 12) + (6 × 16)] = 327.2 g

Putting values in above equation, we get:

$\text{Mass percent of lead}=\frac{207.2g}{327.2g}\times 0100=63.32\%$

Hence, the mass percent of lead in lead (IV) carbonate is 63.32 %

4 0

3 years ago

Hey, if anyone is really good at Chemistry can you please let me know? I can give either my pa dlet or my email, thanks :)

Vesnalui [34]

Answer:

i'm pretty good at it

Explanation:

8 0

2 years ago

Read 2 more answers

Suppose you have 100 grams of radioactive plutonium-239 with a half-life of 24,000 years. how many grams of plutonium-239 will r

Alexandra [31]

To solve this problem, let us first calculate for the rate constant k using the half life formula:

t1/2 = ln 2 / k

where t1/2 = half life period = 24,000 years, therefore k is:

k = ln 2 / 24,000

k = 2.89 x 10^-5 / yr

Now we use the rate equation:

A = Ao e^(-k t)

where,

A = mass of Plutonium-239 after number of years

Ao = initial mass of Plutonium-239

t = number of years

A. t = 12,000 years, find A

A = 100g e^(- 2.89 x 10^-5 * 12,000)

A = 70.7 g

B. t = 24,000 years, find A

A = 100g e^(- 2.89 x 10^-5 * 24,000)

A = 50 g

C. t = 96,000 years, find A

A = 100g e^(- 2.89 x 10^-5 * 96,000)

A = 6.24 g

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3 years ago

Explică rolul chimiei în protejarea mediului înconjurător?

Degger [83]

Answer:

Chimia ne poate ajuta să înțelegem, monitorizăm, protejăm și îmbunătățim mediul din jurul nostru. Chimiștii dezvoltă instrumente și tehnici pentru a ne asigura că putem vedea și măsura poluarea aerului și a apei.

Explanation: I speak english i just know Romanian language

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3 years ago