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MArishka [77]
2 years ago
15

When salt is dissolved in water, the salt particles are referred to as the _____.

Chemistry
2 answers:
Sergio039 [100]2 years ago
5 0
The salt is a solid compound and is considered the "Solute" of the solution.
Naddika [18.5K]2 years ago
5 0

The correct answer is D. Solute

Explanation:

In a solution, there are two main substances or elements involved these are the solute and the solvent. The solvent refers to the liquid such as water that dissolves another substance that is the solute. In this way, the solute is the substance that integrates or dissolves in the liquid or solvent and this can be liquid or solid. According to this, in the case presented the water is the solvent, the salt is the solute, and the final substance is the solution. Thus, the salt particles are referred to as the solute.

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Answer:

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3 years ago
Rhodium crystallizes in a face-centered cubic unit cell. The radius of a rhodium atom is 135 pm. Determine the density of rhodiu
Deffense [45]

Answer:

Density of unit cell ( rhodium) = 12.279 g/cm³

Explanation:

Given that:

The radius (r) of a rhodium atom = 135 pm

The atomic mass of rhodium = 102.90 amu

For a face-centered cubic unit cell,

r = \dfrac{a}{2\sqrt{2}}

where;

a = edge length.

Making "a" the subject of the formula:

a = 2 \sqrt{2} \times r

a = 2 \times 1.414 \times 135 \ pm

a = 381.8 pm

to cm, we get:

a = 381.8 × 10⁻¹⁰ cm

However, recall that:

density \ of \ unit \ cell = \dfrac{mass \ of \ unit \ cell}{volume \ of \unit \ cell}

where;

mass of unit cell = mass of atom × numbers of atoms per unit cell

Also;

mass\  of\ atom =\dfrac{ atomic \ mass}{Avogadro  \  number}

mass\  of\ atom =\dfrac{ 102.9}{6.023 \times 10^{23}}

Recall also that number of atoms in a unit cell for a  face-centered cubic = 4

So;

mass \ of \ unit \ cell= \dfrac{102.90}{6.023 \times 10^{23}}\times 4

mass of unit cell = 6.83380375 × 10⁻²² g

Density  \ of  \ unit \  cell = \dfrac{6.83380375 \times 10^{-22}}{(381.8\times 10^{-10})^3}

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[Ar] 4s²
Let me know if you want a step by step!
Hope that helps
4 0
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Read 2 more answers
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