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MArishka [77]
3 years ago
15

When salt is dissolved in water, the salt particles are referred to as the _____.

Chemistry
2 answers:
Sergio039 [100]3 years ago
5 0
The salt is a solid compound and is considered the "Solute" of the solution.
Naddika [18.5K]3 years ago
5 0

The correct answer is D. Solute

Explanation:

In a solution, there are two main substances or elements involved these are the solute and the solvent. The solvent refers to the liquid such as water that dissolves another substance that is the solute. In this way, the solute is the substance that integrates or dissolves in the liquid or solvent and this can be liquid or solid. According to this, in the case presented the water is the solvent, the salt is the solute, and the final substance is the solution. Thus, the salt particles are referred to as the solute.

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Lera25 [3.4K]
I think b would make the most sense.
5 0
3 years ago
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an atom has 70 protons, 70 electrons, and 99 neutrons. what is the mass number? group of answer choices
Blizzard [7]

Answer:

169

Explanation:

protons+neutrons=atomic mass

70+99=169

6 0
3 years ago
An aqueous solution of cesium chloride is prepared by dissolving 52.3 g cesium chloride in 60.0g of water at 25°C. The volume of
LekaFEV [45]

Given data:

Mass of cesium chloride CsCl (m) = 52.3 g

Mass of water (mh2O)= 60.0 g

Volume of the solution (V) = 63.3 ml

Step 1: Calculate the number of moles of CsCl

Molar mass of CsCl = 168.36 g/mol

Mass of CsCl = 52.3 g

# moles = mass/molar mass = 52.3 g/168.36 g.mol-1 = 0.3106 moles

Step 2: Volume of solution in Liters

1000 ml = 1 liter

therefore, 63.3 ml corresponds to : 63.3 ml * 1 L/1000 ml = 0.0633 L

Step 3: Calculate molarity of CsCl

Molarity = moles of CsCl/volume of solution

            = 0.3106 moles/0.0633 L = 4.91 moles/L

Molarity = 4.91 M


7 0
3 years ago
Express 250,000 mL in liters.<br> A) 0.25 L <br> B) 2,500 L <br> C) 25 L <br> D) 250 L
elena-s [515]
D) 250l
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250,000/1000
5 0
3 years ago
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Given the values for C (2.5) and O (3.5), calculate the electronegativity difference in a carbon monoxide bond, CO
34kurt

Answer:

ΔEN CO   = 1.0

Explanation:

To calculate the electronegativity difference, we have to substract the element which has the highest EN to the other, that has a low value.

For this case EN from O - EN from C

Electronegativity is a property of the periodic table that increases diagonally, where Fr and Rb are the elements of less EN while F is the most electronegative element, with a value of 4. This is because F is an element with a high ionization energy and a negative electronic affinity.

ΔEN CO  = 3.5 - 2.5 = 1.0

Electronegativity (EN) describes the ability of an atom to compete for

electrons with other atoms to which it is attached.

7 0
4 years ago
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