'The Sedimentary rock formed from years of sediments piling on top of it and being compressed.'
Answer:
Both b/c a chemical formula tells you how many and a sketch formula shows how they are bonded together.
Molecular formulas show how many atoms of each element one molecule of a compound contains. Note: Ionic compounds are generally crystalline solids with high melting points. Other compounds, however, have very different properties.
Answer:
Cell Membrane
The thin, flexible outer covering of a cell. It controls what enters and leaves a cell.
Explanation:
Answer:
The correct option is C.
Solutions with low pH values have sour taste.
Explanation:
Low pH value show acidic property which can be define as , -log of conc. of hydrogen ion.
Acid has following properties
- Sour taste
- Turn blue litmus into red
- corrosive
-OH group: Base have OH groups. So it is not correct option so it not correct for low pH i.e. acid
turns litmus paper blue: Base turn red litmus into blue, so it not correct for low pH i.e. acid
feels slippery: Bases are mostly slippery like soap
tastes sour: Sour taste is for acid and bitter taste is for base. So it is correct option for acid
<u>Answer:</u> The pH value of the solution is 10 and the solution is basic in nature.
<u>Explanation:</u>
To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOH of the solution, we use the equation:
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
We are given:
![[OH^-]=1\times 10^{-4}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1%5Ctimes%2010%5E%7B-4%7DM)
Putting values in above equation, we get:

To calculate pH of the solution, we use the equation:

There are three types of solution: acidic, basic and neutral
To determine the type of solution, we look at the pH values.
- The pH range of acidic solution is 0 to 6.9
- The pH range of basic solution is 7.1 to 14
- The pH of neutral solution is 7.
As, the pH of the solution is 10 and is lying in the range of basic solution, so the solution is basic in nature.