You use the equation wavelength= 4 x length of pipe/ number of the harmonic so your wavelength is 1.45.
Answer:
38.7 °C.
The final temperature (reached by both copper and water) is 38.7 °C.
So the answer is probably C.
<span>62 x 9.8 x 12= 7 291.2! Hope this is helpful!</span>
Answer:
-0.9 m/s²
Explanation:
t = Time taken by the hockey puck = 7 seconds
u = Initial velocity of the hockey puck = 13 m/s
v = Final velocity of the hockey puck = 6.7 m/s
a = Acceleration of the hockey puck
Equation of motion
![v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{6.7-13}{7}\\\Rightarrow a=-0.9\ m/s^2](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%20a%3D%5Cfrac%7Bv-u%7D%7Bt%7D%5C%5C%5CRightarrow%20a%3D%5Cfrac%7B6.7-13%7D%7B7%7D%5C%5C%5CRightarrow%20a%3D-0.9%5C%20m%2Fs%5E2)
The acceleration of the hockey puck in the seven seconds is -0.9 m/s²
The acceleration due to gravity is not needed to find the acceleration of the puck.
Answer:
(a) right
(b) λ = 4.65m
(c) v = 1519m/s
(d) f = 327Hz
Explanation:
The characteristic sinusoidal pressure fluctuation equation for a wave traveling to the right is given as
P(x,t) = BkASin(kx-ωt)
Where
B = Bulk modulus
k = wave number
A = displacement amplitude
x = position on the x-axis
ω = angular frequency
t = time t
(a) the wave is travelling to the right
(b) from the given equation
ΔP(x,t) = (24.0 / r) sin(1.35r - 2050t)
1.35 compares with k
So k = 1.35rad/m
And k = 2π/ λ
λ = 2π/k = 2π/1.35 = 4.65m
(c) ω =kv
From the given equation ω = 2050 rad/s
v = ω/k = 2050/1.35 = 1519m/s
(d) f = v/λ =1519/4.65 = 327Hz