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likoan [24]
3 years ago
5

If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front o

f the lens what is the height of the image
Chemistry
1 answer:
Westkost [7]3 years ago
4 0

Answer:The height of the image is -6 mm.

Explanation;

Distance of the object form the lens = u = 12 mm

Distance of the image formed from the lens = v = 4 mm

Height of the object = 18 mm=h_o

The magnification is given by :

M=-\frac{v}{u}=\frac{h_i}{h_o}

h_i\& h_o= Height of an image and object respectively.

M=-\frac{4 mm}{12 mm}=\frac{h_i}{18 mm}

h_i=-6 mm

The height of the image is -6 mm.The image formed is real and negative sign signifies that image is inverted.

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